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4 years ago

Help me with this question

Mathematics

2 answers:

VMariaS [17]4 years ago

8 0

C 60

Step-by-step explanation:

110 minus 50 equals 60

( my mistake for the last answer )

kondaur [170]4 years ago

3 0

Answer:

Its C

Step-by-step explanation:

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PLEASE HELP I need the answer for this ASAP pleaseeeee

True [87]

Answer:

Step-by-step explanation:

$f(x) = 5 \sqrt{x} + 8 \\ f(1) = 5 \sqrt{1} + 8 \\13$

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3 years ago

Find the value of h(x) = -3x – 12 when x = -2? Show work

7nadin3 [17]

Answer:

-6

Step-by-step explanation:

h(x) = -3x – 12 becomes h(-2) = -3(-2) – 12 = -6

7 0

3 years ago

What is 875x132 written out in long multiplication

lukranit [14]

857 x 132= 113,124
work is showed in the image

7 0

3 years ago

Among all right circular cones with a slant height of 24, what are the dimensions (radius and height) that maximize the volum

aleksklad [387]

Answer:

5571.99

Step-by-step explanation:

We need to use the Pythagorean theorem to solve the problem.

The theorem indicates that,

$r^2+h^2=24^2 \\r^2+h^2=576\\r^2=576-h^2$

Once this is defined, we proceed to define the volume of a cone,

$v=\frac{1}{3}\pi r^2 h$

Substituting,

$v=\frac{1}{3} \pi (576-h^2)h\\v=\frac{1}{3} \pi (576h-h^3)$

We need to find the maximum height, so we proceed to calculate h, by means of its derivative and equalizing 0,

$\frac{dv}{dh} = \frac{1}{3} \pi (576-3h^2)$

$\frac{dv}{dh} = 0$ then $\rightarrow \frac{1}{3}\pi(576-3h^2)=0$

$h_1=-8\sqrt{3}\\h_2=8\sqrt{3}$

<em>We select the positiv value.</em>

We have then,

$r^2 = 576-(8\sqrt3)^2 = 384\\r=\sqrt{384}$

We can now calculate the maximum volume,

$V_{max}= \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi (\sqrt{384})^2 (8\sqrt{3}) = 5571.99$

4 0

3 years ago

Evaluate.<br><br><br><br> 2⋅((42)−1)

Nana76 [90]

Answer:

Hi there!

Your answer is:

<em />

<em>Question was unclear! See below for answer possibilities!</em>

Step-by-step explanation:

<u>IF "-1" MEANS MULTIPLY BY NEGATIVE 1</u>

2((42) -1 ))

2(-42)

<u>IF "-1" MEANS SUBTRACT 1</u>

2((42)-1)

2(41)

Hope this helps

5 0

4 years ago