An apartment has

Evaluate 3x for x = -2, x = 1, and x = 3.

marusya05 [52]

Option A is correct.

Put the values of x in 3^x and you will get the answer corresponding to option A

5 0

1 year ago

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What is the y-intercept of the exponential function? f(x)=−32(2)x−3+3 Enter your answer in the box.

Bogdan [553]

y-intercept for x = 0.

Substitute x = 0 to the equation of the function:

$f(x)=-32(2)^{x-3}+3\\\\f(0)=-32(2)^{0-3}+3=-32(2)^{-3}+3=-32\cdot\dfrac{1}{2^3}+3=-32\cdot\dfrac{1}{8}+3\\\\=-4+3=-1\\\\Answer:\ \boxed{y-intercept=-1\to(0,\ -1)}$

6 0

3 years ago

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1. Find all the zeros of the polynomial P(x) = 2x^3 – x^2 – 4x+3<br>

umka21 [38]

Answer:

nicce

Step-by-step explanation:

4 0

3 years ago

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Which equation results from taking the square root of both sides of (x 9)2 = 25? x 3 = ±5 x 3 = ±25 x 9 = ±5 x 9 = ±25.

kow [346]

The equation which is results from taking the square root of both sides of the provided equation is,

$(x+9)=\pm5\\$

<h3>What is the square root?</h3>

A square root of a number is the value which is when multiplicand by itself gives the same value as the number posses.

Let a number is <em>a. </em>Then this number in the form of square root can be written as,

$a=\sqrt{a}\times \sqrt{a}$

The given algebraic equation in the problem is,

$(x+ 9)^2 = 25$

Take the square root, in both sides,

$\sqrt{(x+ 9)^2} = \sqrt{25}\\\sqrt{(x+ 9)^2} = \sqrt{5^2}$

Cancel out the square root with the square of the number as,

$(x+9)=\pm5\\$

Hence, the equation which is results from taking the square root of both sides of the provided equation is,

$(x+9)=\pm5\\$

Learn more about the square root of number here;

brainly.com/question/664132

7 0

2 years ago

a port and a radar station are 2 mi apart on a straight shore running east and west. a ship leaves the port at noon traveling no

Rom4ik [11]

Answer:

The rate of change of the tracking angle is 0.05599 rad/sec

Step-by-step explanation:

Here the ship is traveling at 15 mi/hr north east and

Port to Radar station = 2 miles

Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles

Therefore the ship, port and radar makes a triangle with sides

2, 7.5 and x

The value of x is gotten from cosine rule as follows

x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04

x = 6.25 miles

By sine rule we have

$\frac{sin A}{a} = \frac{sin B}{b}$

Therefore,

$\frac{sin 45}{6.25} = \frac{sin \alpha }{7.5}$

α = Angle between radar and ship α

∴ α = 58.052

Where we put

$\frac{sin 45}{6.25} = \frac{sin \alpha }{x}$ to get

$\frac{x}{6.25} = \frac{sin \alpha }{sin 45}$ and differentiate to get

$\frac{\frac{dx}{dt} }{6.25} = cos\alpha\frac{\frac{d\alpha }{dt} }{sin 45}$

$\frac{15sin45 }{6.25cos\alpha } =\frac{d\alpha }{dt} }$ = 3.208 degrees/second = 0.05599 rad/sec.

6 0

3 years ago