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pishuonlain [190]
3 years ago
14

The graph below shows a quadratic function f(x) and an absolute value function g(x)

Mathematics
1 answer:
Sophie [7]3 years ago
6 0

Answer:

The x-values that are approximate solution of the equation f(x) = g(x) are x_{1} \approx -3.5 and x_{2}\approx 5, respectively.

Step-by-step explanation:

From graph we infer that the x-values that represents a solution to the system of equations corresponds to those values of x in which both functions coincide. As we see, there are two x-values for f(x) = g(x), which are described below:

x_{1} \approx -3.5 and x_{2}\approx 5

The x-values that are approximate solution of the equation f(x) = g(x) are x_{1} \approx -3.5 and x_{2}\approx 5, respectively.

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Find the absolute value and the opposite of the integer. –98
Lena [83]
<span>Absolute value of -98 is 98

Hope I helped:D </span>
3 0
3 years ago
Read 2 more answers
1. Select all values of x that are solutions to the equation: -2(x + 4)(3x - 18) = 0A) -6B) -4C) -2D) OE) 2F) 4G) 6
navik [9.2K]
\begin{gathered} -2(x+4)(3x-18)=0 \\ \text{There are two factors here which are} \\ -2(x+4)\text{ and} \\ (3x-18) \\ \text{This means, either} \\ 2(x+4)=0 \\ 2x+8=0 \\ 2x=-8 \\ \text{Divide both sides by 2} \\ x=-4 \\ OR \\ 3x-18=0 \\ 3x=18 \\ \text{Divide both sides by 3} \\ x=6 \\ \text{Therefore,} \\ x=-4\text{ or} \\ x=6 \end{gathered}

x = -4 OR x = 6

The correct options are B and G

6 0
1 year ago
8-1×0+2÷2=? It looks easy, so many different results.
kvasek [131]
You have to use PEMDAS.

8-1*0+2/2 \\  \\ 8-0+2/2 \\  \\ 8-0+1 \\  \\ 8+1 \\  \\ 9
8 0
3 years ago
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<img src="https://tex.z-dn.net/?f=0.07%20%5Ctimes%201.22" id="TexFormula1" title="0.07 \times 1.22" alt="0.07 \times 1.22" align
Alex_Xolod [135]

Answer:

0.0854

Step-by-step explanation:

0.07 \times 1.22  = 0.0854


Please mark brainliest. Have a great day!

3 0
3 years ago
Look at the rectangle and the square:
OlgaM077 [116]

Answer:

Sam is incorrect

Step-by-step explanation:

We can calculate the lengths of the diagonals using Pythagoras' identity.

The diagonals divide the rectangle and square into 2 right triangles.

Consider Δ SRQ from the rectangle

SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )

SQ = \sqrt{180} ≈ 13.4 in ( to 1 dec. place )

Consider Δ ONM from the square

OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )

OM = \sqrt{72} ≈ 8.5 in ( to 1 dec. place )

Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4

Then diagonal OM is not twice the length of diagonal SQ

5 0
2 years ago
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