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Rasek [7]
3 years ago
6

Please help, is it possible to draw a triangle with sides 6 inches, 4 inches, and 2 inches. If not, why?

Mathematics
1 answer:
Liula [17]3 years ago
8 0
According to the Triangle Inequality Theorem any two sides of a triangle must be greater than the third side.

a+b>c

b+c>a

c+a>b

So let's say that 2=a 4=b and 6=c.

2+4>6 is incorrect because 6 is not greater than 6

4+6>2 is correct because 10 is greater than 2

2+6>4 is correct because 8 is greater than 4

All three must be true for you to be able to draw the triangle. So no you cannot draw a triangle with the sides 6, 4, and 2.
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What is the inverse of the function f(x) = x +3
Nezavi [6.7K]

Answer:

h(x) = x-3

Step-by-step explanation:

The inverse of a function works such that f(h(x)) = x. Also, f(h(x)) = h(x) + 3. Thus, x = h(x) +3 -> h(x) = x-3

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5 0
3 years ago
Given that f(3)=9,f′(3)=3,g(9)=3, and g′(9)=5, what is the approximate value of g(f(3.02))?
Sati [7]
F(3) = 9
f'(3) = 3
L(x) = linear approximation to f(x) at x = a
L(x) = linear approximation to f(x) at x = 3
L(x) = f'(a)*(x-a)+f(a)
L(x) = f'(3)*(x-3)+f(3)
L(x) = 3*(x-3)+9
L(x) = 3x-9+9
L(x) = 3x
L(3.02) = 3*3.02
L(3.02) = 9.06
So f(3.02) is approximately 9.06 based on the L(x) linear approximation

g(9) = 3
g'(9) = 5
M(x) = linear approximation to g(x) at x = 9
M(x) = linear approximation to g(x) at x = a
M(x) = g'(a)*(x-a)+g(a)
M(x) = g'(9)*(x-9)+g(9)
M(x) = 5*(x-9)+3
M(x) = 5x-45+3
M(x) = 5x-42
M(9.06) = 5*9.06-42
M(9.06) = 3.3

So g(9.06) is approximately equal to 3.3 based on the linear approximation M(x)

In summary, this means
g(9.06) = g(f(3.02)) = 3.3
which are approximations

The final answer is 3.3
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