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Sergio039 [100]
2 years ago
12

Find the distance across the lake. Assume the triangles are similar.

Mathematics
2 answers:
irina1246 [14]2 years ago
4 0

Answer:

a

Step-by-step explanation:

babunello [35]2 years ago
4 0

Answer:

A.   L = 240 m

Step-by-step explanation:

<u>use similar triangle </u>

L / 60 = 80 / 20

L = (80 * 60) / 20

L = 240 m

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In 2002, the number of students in a large urban high school was 2260. In 2004, the number of students was 2230. If the number o
Alchen [17]
Its saying that every 2 years the students decreases by 30 such as in 1990 the number of students in an large urban high school is 3490.In 1992 the number of students was 3460 and keep decreasing every 2 years 30 comes off.
The easiest way to move faster is to:
Years=The Number Of Students
2006=2200
2008=2170
2010=2140
2012=2110
2014=2080
2016=2050
But here is the tricky part the question said 2017 it an odd number so we have half of 30 because 30 comes of every 2 years but its the 1st year so it half of the 2 years and half of 30 students so this equals to:
2017=2035
8 0
3 years ago
2415÷23<br>step by step pls​
pashok25 [27]

Answer:

See below.

Step-by-step explanation:

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6 0
2 years ago
Read 2 more answers
The area of a trapezium is 35 cm² and the distance between its parallel sides is 16 cm. if one of the parallel is of length 25 c
Furkat [3]

Answer:

No solution

Step-by-step explanation:

A = (b1 + b2)h/2

A = 35 cm²

h = 16 cm

b1 = 25 cm

b2 = ?

35 = (25 + b2)(16)/2

70 = (25 + b2)(16)

70 = 400 + 16b2

16b2 = 330

b2 = 330/16 = -20.625

The answer is a negative number. Since the base of a trapezium cannot have a negative length, there does not exist a trapezium with the given information.

3 0
2 years ago
A consumer organization estimates that over a​ 1-year period 16​% of cars will need to be repaired​ once, 9​% will need repairs​
Mice21 [21]

Answer:

A consumer organization estimates that over a​ 1-year period 16​% of cars will need to be repaired​ once, 9​% will need repairs​ twice, and 3​% will require three or more repairs..

We have the cars that do not need repair =100-(16+9+3)=72%

(16+9+3=28% cars need repair of some sort)

What is the probability that  :

​a) neither will need​ repair? ​

=> 0.72\times0.72=0.5184

b) both will need​ repair? ​

=> 0.28\times0.28=0.0784

c) at least one car will need​ repair?

=> 1-(0.72\times0.72)

=> 1-0.5184=0.4816

5 0
3 years ago
Write 13.64 in expanded form​
STALIN [3.7K]

Answer: 10 + 3 + 0.6 + 0.04

Step-by-step explanation:

You write the value of each digit as addends.

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2 years ago
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