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liberstina [14]
3 years ago
14

Which graph represents the solution set of the inequality x+226?

Mathematics
1 answer:
vekshin13 years ago
4 0

Answer:1

Step-by-step explanation:

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(6 + 4(-12) =<br> i need help on this one too..
OlgaM077 [116]

Answer:

-42

Step-by-step explanation:

3 0
3 years ago
A chicken salad recipe calls for 1 8
NARA [144]

Answer: 1.0625\ pounds or \frac{17}{16}\ pounds

Step-by-step explanation:

The complete exercise is: "A chicken salad recipe calls for \frac{1}{8} pound of chicken per serving . How many pounds of chicken are needed to make 8\frac{1}{2}  serving".

You can convert the Mixed number to a Decimal number. Divide the numerator 1 by the denominator 2 and then add the quotient to the Whole number. Then, you get:

8+0.5=8.5

Now divide the numerator 1 by the denominator 8 to write the fraction to a Decimal number. Then:

\frac{1}{8}= 0.125

Let be "x" the amount of pounds are needed to make 8\frac{1}{2}  serving.

Then, you can set up the following proportion:

\frac{1}{0.125}=\frac{8.5}{x}

Solving for "x", you get:

\frac{1}{0.125}=\frac{8.5}{x}\\\\x(\frac{1}{0.125})=8.5\\\\x=8.5*0.125\\\\x=1.0625

or \frac{17}{16}\ pounds

7 0
3 years ago
What would the answer be
ArbitrLikvidat [17]

Answer:

12x^4-35x^3+45x^2-13x-15

Step-by-step explanation:

some issues with the signa

3 0
3 years ago
Doc Brown’s DeLorean has three crucial systems that are required for a successful trip: combustion engine, time circuits, and fl
Nesterboy [21]

Step-by-step explanation:

The total probability that the DeLorean makes the trip is:

P = P(engine) × P(at least 1 time circuit) × P(at least 2 capacitors)

P = P(engine) × (1 − P(0 time circuits)) × P(at least 2 capacitors)

P = 0.94 × (1 − ₄C₀ 0.75⁰ 0.25⁴) × (₃C₂ 0.8² 0.2¹ + ₃C₃ 0.8³ 0.2⁰)

P = 0.94 × (1 − 0.25⁴) × (0.384 + 0.512)

P = 0.83895

The reliability of the DeLorean is approximately 83.9%.

3 0
3 years ago
Another question I'm stuck on
qwelly [4]
M=(y2-y1)/(x2-x1) m=(-4-4)/(3-1) m=-8/2 m=-4 so the answer should be first one
7 0
3 years ago
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