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fgiga [73]
3 years ago
14

What is the distance between the points (−3, 5) and (−3, −6) ?

Mathematics
1 answer:
tresset_1 [31]3 years ago
8 0
The answer would be D, 11 units! :)
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Westkost [7]

Answer:

math is a difficult subject

7 0
2 years ago
which of the following expresses the coordinates of the foci of the conic section shown below? (x-2)^2/4+(y+5)^2/9
elena55 [62]

Step-by-step explanation:

\frac{(x - 2) {}^{2} }{4}  +  \frac{(y + 5) {}^{2} }{9}  = 1

This is the equation of the ellipse. Since the denominator is greater for the y values, we have a vertical ellipse. Remember a>b, so a

The formula for the foci of the vertical ellipse is

(h,k+c) and (h,k-c).

where c is

Our center (h,k) is (2, -5)

{c}^{2}  =  {a}^{2}  -  {b}^{2}

Here a^2 is 9, b^2 is 4.

{c}^{2}  = 9 - 4

{c}^{2}  = 5

c =  \sqrt{5}

So our foci is

(2, - 5 +  \sqrt{5} )

and

(2, - 5 -  \sqrt{5} )

6 0
1 year ago
Which proportion can be used to show that the slope of AC is equal to the slope of CE?
Gnesinka [82]

Slope is given by the expression:

m=\frac{y_2-y_1}{x_2-x_1}

We can equal both slopes of mAC and mCE

\begin{gathered} \frac{3-6}{-1-(-3)}=\frac{-3-3}{3-(-1)} \\  \\ \frac{-3}{2}=-\frac{6}{4} \\ -\frac{3}{2}=-\frac{3}{2} \end{gathered}

Answer is B.

5 0
1 year ago
What is the derivative of the function below?
11111nata11111 [884]

g(x)=4x-\dfrac{1}{4x}=4x-(4x)^{-1}\\\\\\\\g'(x)=\left[4x-(4x)^{-1}\right]'=(4x)'-\left[(4x)^{-1}\right]'=4-[-1(4x)^{-2}]\cdot4\\\\=4+\dfrac{1}{(4x)^2}\cdot4=4+\dfrac{4}{4^2x^2}=\boxed{4+\dfrac{1}{4x^2}}\\\\Used:\\\\(f(x)-g(x))'=f'(x)-g'(x)\\\\.[f(g(x))]'=f'(g(x))\cdot g'(x)\\\\(x^n)'=nx^{n-1}

8 0
2 years ago
Solve the equation :<br>-3 • ( 2 - x ) + 4 = 2 • ( 1 - 2x) + 3<br>thanks :) ​
kakasveta [241]

Isolate the variable by dividing each side by factors that don't contain the variable.

x  =  1

-6+3x+4=2-4x+3

-8+7x+1=0

7x=7

x=1

4 0
2 years ago
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