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2 years ago

Which equation represents the line shown on he graph?

Mathematics

1 answer:

hichkok12 [17]2 years ago

4 0

It is the first one ...w= 3z+2

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Cole gets paid $5,000 plus 16% of all his popcorn sales,x, while Michael gets A fixed salary of $55,000.Write an inequality that

Hitman42 [59]

Answer:

5000 + (0.16)x > 55,000

Step-by-step explanation:

DATA:

Michael's salary = $55,000

Cole's basic salary = $5,000

--> Commission = 16% of sales

--> Sales = x

Cole's total salary

--> Basic salary + Commission x sales

--> 5000 + 16% of x

--> 5000 + (0.16)x as 16 percent is equal to 16/100 = 0.16

Cole's total salary should be more than Michael's total salary

5000 + (0.16)x > 55000

--> Make x the subject

0.16x > 55000-5000

0.16x > 50,000

x > 50,000/0.16

x > 312500

The inequality that represents the dollar amount of sales is 5000 + (0.16)x > 55000.

The dollar amount of sales that Cole must generate should be more than $312500.

4 0

3 years ago

An environment engineer measures the amount ( by weight) of particulate pollution in air samples ( of a certain volume ) collect

Serggg [28]

Answer:

$k = 1$

$P(x > 3y) = \frac{2}{3}$

Step-by-step explanation:

Given

$f \left(x,y \right) = \left{ \begin{array} { l l } { k , } & { 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x } & { \text 0, { elsewhere. } } \end{array} \right.$

Solving (a):

Find k

To solve for k, we use the definition of joint probability function:

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, = 1$

Where

${ 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x }$

Substitute values for the interval of x and y respectively

So, we have:

$\int\limits^2_{0} \int\limits^{x/2}_{0} {k\ dy\ dx} \, = 1$

Isolate k

$k \int\limits^2_{0} \int\limits^{x/2}_{0} {dy\ dx} \, = 1$

Integrate y, leave x:

$k \int\limits^2_{0} y {dx} \, [0,x/2]= 1$

Substitute 0 and x/2 for y

$k \int\limits^2_{0} (x/2 - 0) {dx} \,= 1$

$k \int\limits^2_{0} \frac{x}{2} {dx} \,= 1$

Integrate x

$k * \frac{x^2}{2*2} [0,2]= 1$

$k * \frac{x^2}{4} [0,2]= 1$

Substitute 0 and 2 for x

$k *[ \frac{2^2}{4} - \frac{0^2}{4} ]= 1$

$k *[ \frac{4}{4} - \frac{0}{4} ]= 1$

$k *[ 1-0 ]= 1$

$k *[ 1]= 1$

$k = 1$

Solving (b): $P(x > 3y)$

We have:

$f(x,y) = k$

Where $k = 1$

$f(x,y) = 1$

To find $P(x > 3y)$ , we use:

$\int\limits^a_b \int\limits^a_b {f(x,y)}$

So, we have:

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {f(x,y)} dxdy$

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {1} dxdy$

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 dxdy$

Integrate x leave y

$P(x > 3y) = \int\limits^2_0 x [0,y/3]dy$

Substitute 0 and y/3 for x

$P(x > 3y) = \int\limits^2_0 [y/3 - 0]dy$

$P(x > 3y) = \int\limits^2_0 y/3\ dy$

Integrate

$P(x > 3y) = \frac{y^2}{2*3} [0,2]$

$P(x > 3y) = \frac{y^2}{6} [0,2]\\$

Substitute 0 and 2 for y

$P(x > 3y) = \frac{2^2}{6} -\frac{0^2}{6}$

$P(x > 3y) = \frac{4}{6} -\frac{0}{6}$

$P(x > 3y) = \frac{4}{6}$

$P(x > 3y) = \frac{2}{3}$

8 0

2 years ago

For his yearly vacation, Colton plans to spend $350 on train tickets, $200 on food, $150 on accommodations, and $50 on miscellan

scoundrel [369]

Answer: He would spend 750$ on the entire vacation.

Step-by-step explanation: Simple addition, 350+150 (Always do the two odd ones first) which equals 500, 500+200 equals 700, and 700+50 equals 750, which gives your answer of 750$'s for the whole vacation.

5 0

2 years ago

Read 2 more answers

PLEASE HELPP!!! Please

seraphim [82]

Answer:

a: the second choice, and pounds=10

b. the second choice, and points=90.

Step-by-step explanation:

for a , you just divide the pounds by the price and you get 5 for each.

for b, you just divide the points by the tickets and you get 9 each.

7 0

1 year ago

If u=(1,3) and v=(2,6), find u+v

Ronch [10]

Answer:

(3,9)

Step-by-step explanation:

u=(1,3) and v=(2,6),

u+v = (1+2, 3+6)

=(3,9)

8 0

2 years ago

Read 2 more answers