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3 years ago

What is the value if m in the equation 1\2m-3/4n=16 when n=8

1 answer:

6 0

$\frac{1}{2}m-\frac{3}{4}n=16\ \ \ \ \ \ \ \ \ \ \ \ n=8\\\\\frac{1}{2}m-\frac{3}{4}\cdot8=16\\\\\frac{1}{2}m-6=16\\\\\frac{1}{2}m=16+6\\\\\frac{1}{2}m=22\ \ \ \ \ \ \ \ |\cdot2\\\\m=44$

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What is the area of the trapezoid?

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Answer:

the area of a trapezoid is equal to half the product of the height and the sum of the two bases. Area = ½ x (Sum of parallel sides) x (perpendicular distance between the parallel sides).

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3 years ago

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What is the answer of 7/4(-4)?

vampirchik [111]

7/4 means you have to do 7 divided 4. You would get 1.75 then you have to do 1.75 times -4. You get -7. -7 is the answer.

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A pile of newspaper was 17 3/4 inches high. Each consecutive week for the next 5 weeks the height of pile increase by 8 7/12 inc

Murljashka [212]

Answer: the height in inches, of the pile after 3 weeks is 34 11/12 inches

Step-by-step explanation:

Each consecutive week for the next 5 weeks the height of pile increase by 8 7/12 inches. Converting 8 7/12 inches to improper fraction, it becomes 103/12 inches. The height is increasing in an arithmetic progression. The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = 17 3/4= 71/4 inches

d = 103/12 inches

n = 3 weeks

the height in inches, of the pile after 3 weeks, T3. Therefore,

T3 = 71/4 + (3 - 1)103/12

T3 = 71/4 + 2 × 103/12 = 71/4 + 103/6

T3 = 419/12 inches = 34 11/12 inches

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3 years ago

The current student population of the Brentwood Student Center is 2,000. The enrollment at the center increases at a rate of 4%

swat32

Answer:

2249.728 so the answer would be 2250

Step-by-step explanation

2000(1.04)^3 you can change the 3 out for any number to find the population for any given year.

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3 years ago

You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us

Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that

step 1

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$r=10\%=10/100=0.10\\n=4$

substitute in the formula above

$A=P(1+\frac{0.10}{4})^{4t}$

$A=P(1.025)^{4t}$

Applying property of exponents

$A=P[(1.025)^{4}]^{t}$

$A=P(1.1038)^{t}$

step 2

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$r=10\%=10/100=0.10$

substitute in the formula above

$A=P(e)^{0.10t}$

Applying property of exponents

$A=P[(e)^{0.10}]^{t}$

$A=P(1.1052)^{t}$

step 3

Compare the final amount

$P(1.1052)^{t} > P(1.1038)^{t}$

therefore

Find the difference

$P(1.1052)^{t} - P(1.1038)^{t}$ ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

3 0

3 years ago