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Ierofanga [76]
2 years ago
10

Only number 8 plssss bet no one will get this

Mathematics
1 answer:
8_murik_8 [283]2 years ago
4 0

48 units squared(I think) because the rectangles on the ends are 18 units squared, and the middle rectangle would have to be split into two squares, both equalling 12, and 12 plus 36 is 48

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2x+4-3x=-11 what is the answer
Pie
You want the xs and the numbers on different sides. 
2x-3x=-11-4
-x=-15
divide x by a -1
x=15
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A box contains a $1 bill, a $5 bill, a $10 bill, and a $20 bill. If two bills are selected at random what is the probability tha
pshichka [43]

Answer:

50%

Step-by-step explanation:

Because you can get either 1 and 5 which is 6 or 10 and 1 whoch is 11 but the other two will give you 15+

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Mr. Osterhout is putting trim around the edge of a circular merry-go-round that has a diameter of 15 feet. How much trim does he
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Given:
circular merry-go-round that has a diameter of 15 feet.

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Mr. Osterhout needs to buy 47.10 feet of trim to put around the circular merry-go-round.
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3 years ago
Examine the power.
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An NBA fan named Mark claims that there are more fouls called on his team 1 point
inn [45]

Answer:

t=\frac{12.2-11.5}{\frac{1.6}{\sqrt{34}}}=2.551    

df = n-1=34-1=33

p_v =P(t_{(33)}>2.551)=0.008  

Since the p value is less than the significance level of 0.05 we have enough evidence to reject the null hypothesis in favor of the claim

And the best conclusion for this case would be:

b)The p-value is 0.008, indicating sufficient evidence for his claim.

Step-by-step explanation:

Information provided

\bar X=12.2 represent the sample mean fould against

s=1.6 represent the sample standard deviation

n=34 sample size  

represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is higher than 11.5 fouls per game:  

Null hypothesis:\mu \leq 11.5  

Alternative hypothesis:\mu > 11.5  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

The statistic is given by:

t=\frac{12.2-11.5}{\frac{1.6}{\sqrt{34}}}=2.551    

P value

The degreed of freedom are given by:

df = n-1=34-1=33

Since is a one side test the p value would be:  

p_v =P(t_{(33)}>2.551)=0.008  

Since the p value is less than the significance level of 0.05 we have enough evidence to reject the null hypothesis in favor of the claim

And the best conclusion for this case would be:

b)The p-value is 0.008, indicating sufficient evidence for his claim.

7 0
3 years ago
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