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3 years ago

6

Please help thanks! :DDDDDDDDDDDDDDDDDDDD

1 answer:

Anika [276]3 years ago

3 0

The experimental probability, sometimes known as the relative frequency, is the number of times the 'interesting' event occurs divided by the number of events in total that have occurred.

In your case, the 'interesting' event is rolling a 3. This happened <u>11 times</u>.
The total number of events that have occurred is 7+9+11+6+9+8 = <u>50</u>.

So the experimental probability of rolling a three is 11/50 = <u><em>0.22</em></u>

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If 8x-17=425 soooo then x= A) 62.74 B) 51 C) 47.89 D) 55.25 so what is the answer

vazorg [7]

The correct answer to this problem would be d

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3 years ago

An asymptote for a function f(x) is a straight line which is approached but never reached by f(x).

ladessa [460]

Answer:

True

Step-by-step explanation:

That is the definition of a asymptote. It is approached but will never get to the line.

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4 years ago

Read 2 more answers

Solve the system by elimination.<br> -8X – 10y = 20<br> -8x – 6y = -4

In-s [12.5K]

Answer:

(5, - 6 )

Step-by-step explanation:

Given the 2 equations

- 8x - 10y = 20 → (1)

- 8x - 6y = - 4 → (2)

Multiply (2) by - 1

8x + 6y = 4 → (3)

Add (1) and (3) term by term to eliminate the x- term, that is

- 4y = 24 ( divide both sides by - 4 )

y = - 6

Substitute y = - 6 into either of the 2 equations and solve for x

Substituting into (1)

- 8x - 10(- 6) = 20

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- 8x = - 40 ( divide both sides by - 8 )

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6 0

3 years ago

What is the least common multiple of 3, 4a, 5b, and 6ab?

Free_Kalibri [48]

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3 years ago

The lengths of nails produced in a factory are normally distributed with a mean of 3.34 centimeters and a standard deviation of

Shtirlitz [24]

Answer:

3.47 and 3.21

Step-by-step explanation:

Let us assume the nails length be X

$X \sim N(3.34,0.07^2)$

Value let separated the top 3% is T and for bottom it would be B

$P(X < T)= 0.97$

Now converting, we get

$P(Z < \frac{T-3.34}{0.07})= 0.97$

Based on the normal standard tables, we get

$P(Z < 1.881)= 0.97$

Now compare these two above equations

$\frac{T-3.34}{0.07} = 1.881 \\\\ T = 1.881 \times 0.07 + 3.34 \\\\ = 3.47$

So for top 3% it is 3.47

Now for bottom we applied the same method as shown above

$P(Z < \frac{B-3.34}{0.07})= 0.03$

Based on the normal standard tables, we get

$P(Z < -1.881)= 0.03$

Now compare these two above equations

$\frac{B-3.34}{0.07} = -1.881$

$= -1.881 \times 0.07 + 3.34 \\\\ = 3.21$

hence, for bottom it would be 3.21

7 0

3 years ago