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Phoenix [80]
3 years ago
13

Find the domain and range of f(x)=1/3|-x|+4

Mathematics
1 answer:
ycow [4]3 years ago
4 0

Answer:

Answer in screenshot

Step-by-step explanation:

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PLEASE HELP FAST!!!!!!!!!
Lana71 [14]

Answer:

132 degrees

Step-by-step explanation:

To solve this problem, you need to know a couple of rules

1) Inscribed angle theroem: when an angle is inscribed in a circle and touches the other end (as opposed to ending at the diameter of the circle), the measure of this angle is half of the measure of the arc.

2)Angles of a quadrilateral shape add up to 360 degrees.

3) The angles inside a circle and the angles of the circles arclength adds up to 360 degrees.

So first, solve angle S with inscribed angle theorem. 126/2 = 63

Then, use the rule that all arc angles in a circle add up to 360 degrees to find the arc angle from Q to S. 360-90-126 = 144. Now find angle P with inscribed angle theorem by doing 144/2 = 72.

Now, use the rule that all angles in a quadrilateral add up to 360 to find R. 360-93-72-63 = 132.  

Let me know if this doesn't work, I'll look at it again.

7 0
2 years ago
Write the quadratic function in vertex form. Then identify the vertex.
ddd [48]

Answer:

Step-by-step explanation:

To put the equation into vertex form, we need to complete the square

g(x) = (x^2 - 4x + ...) - 1\\g(x) = (x^2-4x+(\frac{4}{2})^2 ) - 1 - (\frac{4}{2})^2 \\g(x) = (x-2)^2 - 5\\

This is in the form

y = a(x-h)^2 + k\\(h, k)

So, the vertex is (2, -5)

and g(x) = (x-2)^2-5

7 0
3 years ago
The equation shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in ast
Oxana [17]

Answer:

The equation shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in astronomical units, AU. If planet Y is twice the mean distance from the sun as planet X, by what factor is the orbital period increased?

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Karen karlin bought some large frames for $15 each and some small frames for $8 each at a closeout sale. if she bought 22 frames
BaLLatris [955]

small frames ($8): s

large frames ($15): L


Cost:        8s + 15L = 239   ⇒ 1(8s + 15L = 239)   ⇒    8s + 15L = 239  

Quantity:   s  +   L   = 22   ⇒  -8( s  +   L   = 22)   ⇒  <u> -8s   -8 L  = -176 </u>

                                                                                               7L  = 63

                                                                                                  L = 9

Quantity:   s + L = 22 ⇒   s + (9) = 22   ⇒   s = 13

Answer: 13 small frames, 9 Large frames

7 0
3 years ago
Read 2 more answers
What is the best way to prep for math during the summer?
Phoenix [80]

Answer:

https://www.khanacademy.org

Step-by-step explanation:

Khan Academy is free and you can choose by grade level or course. It's a personalized learning experience with videos and practice exercises that includes progress tracking.

6 0
3 years ago
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