Find the domain and range of f(x)=1/3|-x|+4
1 answer:
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Acc. to midpoint theorem,
15={(2x+9) + (4x-15)}/2
⇒ 30=2x+9+4x-15
⇒ 30-9+15=6x
⇒ 36/6=x
⇒6=x
WZ= 4x-15
=4*6-15
=24-15=9
15={(2x+9) + (4x-15)}/2
⇒ 30=2x+9+4x-15
⇒ 30-9+15=6x
⇒ 36/6=x
⇒6=x
WZ= 4x-15
=4*6-15
=24-15=9
Answer:
71
Step-by-step explanation:
The reference angle is always the smallest angle with the x-axis.
The nearest x axis is at 0 or another name for 0 is 360
360 -289 = 71
The reference angle is 71
