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Lynna [10]
3 years ago
7

what is the probability that the first roll is an even number and the second roll is a number greater than 4?

Mathematics
2 answers:
Alex73 [517]3 years ago
6 0
If we are talking about a 6 sided cube, the probability of an even number is 1/2 and the probabiltity of a number greater than 4 is 1/3.
dalvyx [7]3 years ago
3 0
Multipcation i think
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Help I forgot how to do this​
lakkis [162]

Answer:

number 5 is 11 and number 6 is 16

Step-by-step explanation:

you substitute a for 4 bc a equals 4 and than finish the equation 4+7=11

6. you substitute b for 2 and c for 8 and multiply which than is 16

4 0
3 years ago
From a standard deck of cards, a 5-card hand is dealt. Calculate the number of hands that contain 4 diamonds and 1 black king
rjkz [21]

Answer:

1430

Step-by-step explanation:

Given that a standard deck of cards is 52 cards, we have 13 Diamonds and we need 4 diamonds.

Hence, we have 13C4.

Also, we have 4 kings in a standard deck of cards, and in which we have 2 black kings but we need 1 king.

Hence we have a 2C1

Therefore:

13C4 * 2C1

=> 13! ÷ [4! (13 - 4)!] * 2! ÷ [1! (2-1)!]

=> 13! ÷ [4! (9)!]

=> (1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 10 x 11 x 12 x 13) ÷ [(1 x 2 x 3 x 4) (1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9)]

=> (10 x 11 x 12 x 13) ÷ 24

=> (17160 ÷ 24) * (24 ÷ 6)

=> 715

2! ÷ [1! (2-1)!]

=> 2

Hence, we have 715 * 2

=> 1430

Hence, in this case, the correct answer to the question is 1430

7 0
3 years ago
Brainliest for you if you answer!
eduard

<u>To find the constant of proportionality:</u>

  ⇒ must define constant of proportionality

    ⇒ <em>Constant of Proportionality:  ratio of two proportional values at a </em>

       constant value

       ⇒ (in this case) two proportional values are x and y

<u>The ratio between x and y is equal to</u>

  \frac{y}{x} =\frac{66}{1.2}=55

<u>Answer:</u> <u>55</u> or <u>Choice 1</u>

<u></u>

Hope that helps!

7 0
2 years ago
Help me plz ASAP<br> A.2<br> B.1/2<br> C.2/3<br> D.3/2
BARSIC [14]

A

Step-by-step explanation:

First and foremost, we can rule out B and C because they are less than one and would make the hexagon smaller instead of bigger. Now, when we measure the units, we see that it goes up by 2 squares on the graph. So, by process of elimination and measurement, we get the answer of A.

3 0
2 years ago
We're testing the hypothesis that the average boy walks at 18 months of age (H0: p = 18). We assume that the ages at which boys
marusya05 [52]

Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation    

\bar X=19.2 represent the battery life sample mean    

\sigma=2.5 represent the population standard deviation    

n=25 sample size    

\mu_o =18 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:    

Null hypothesis:\mu = 18    

Alternative hypothesis:\mu \neq 18    

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis:\mu \leq 18    

Alternative hypothesis:\mu > 18  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{19.2-18}{\frac{2.5}{\sqrt{25}}}=2.4    

4) P-value    

First we need to calculate the degrees of freedom given by:  

df=n-1=25-1=24  

Since is a two tailed test for parts I and II, the p value would be:    

p_v =2*P(t_{(24)}>2.4)=0.0245

And for part III since we have a one right tailed test the p value is:

p_v =P(t_{(24)}>2.4)=0.0122

5) Conclusion    

I. This finding is significant for a two-tailed test at .05.

Since the p_v. We reject the null hypothesis so we don't have a significant result. FALSE

II. This finding is significant for a two-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

6 0
3 years ago
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