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stellarik [79]
1 year ago
12

Solve the given word problem.

Mathematics
1 answer:
Paladinen [302]1 year ago
8 0

The dimensions of the bulletin board is 2 ft and 9 ft.

Let the width of board = x

Then, the length of board = 7+x

Area of board = 18 ft²

Area of rectangle = L×W

so, (7+x) × x = 18 ft²

7x + x² = 18 ft²

7x + x² + 18 = 0

x² + 9x -2x -18 = 0

x(x+9) -2(x+9) = 0

(x+9) (x-2) = 0

x+9 =0, x -2 = 0

Dimension can not be in negative number, so

x = 2, Width = 2 ft

Length = 2+7 = 9 ft

Hence, the dimensions of board will be:

The width of board = 2 ft

And, the length of bard = 9 ft.

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Answer:

The correct option is;

Both spreads are best described by the standard deviation

Step-by-step explanation:

The given information are;

,                                    College                       High School

High,                              20                               20

Low,                                6                                 3

Q₁,                                   8                                 5.5

Q₃,                                  18                                16

IQR,                                 10                                10.5

Median,                           14                                11

Mean,                              13.3                             11

σ,                                      5.2                             5.4

Checking for outliers, we have

College

Q₁ - 1.5×IQR gives 8 - 1.5×10 = -7

Q₃ + 1.5×IQR gives 18 + 1.5×10 = 33

For high school

Q₁ - 1.5×IQR gives 5.5 - 1.5×10.5 = -10.25

Q₃ + 1.5×IQR gives 16 + 1.5×10.5 = 31.75

Therefore, there are no outliers and the data is representative of the population

From the data, for the college students, it is observed that the difference between the mean, 13.3 and Q₁, 8, and between Q₃, 18 and the mean,13.3 is approximately the standard deviation, σ, 5.2

The difference between the low and the high is also approximately 3 standard deviations

Therefore the college spread is best described by the standard deviation

Similarly for the high school students, the IQR is approximately two standard deviations, the  difference between the mean, 11 and Q₁, 5.5, and between Q₃, 16 and the mean,11 is approximately the standard deviation, σ, 5.4

Therefore the high school spread is also best described by the standard deviation.

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Step-by-step explanation:

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