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nekit [7.7K]
3 years ago
5

Factor the polynomial 3x3-12x2-27x

Mathematics
1 answer:
zheka24 [161]3 years ago
4 0
The GCF is 3x so we have:-

3x(x^2 - 4x - 9)  <---- answer
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Help me. I don't understand. Please help me find X and IK
sertanlavr [38]

Answer:

x=4\\\\y=6\\\\IK=47

Step-by-step explanation:

Two Tangent Theorem: Tangents which meet at same point are equal in length.

Here tangents at J and H meet at I.

Hence\ HI=IJ\\\\y^2-10=4y+2\\\\y^2-4y-12=0\\\\y^2-6y+2y-12=0\\\\y(y-6)+2(y-6)=0\\\\(y-6)(y+2)\\\\y\ can\ not\ be\ negative\ as\ in\ that\ case\ IJ\ will\ be\ negative.\\\\Hence\ y=6\\\\IJ=4y+2=4\times 6+2=26\\\\\\\\Tangents\ at\ J\ and\ L\ meet\ at\ K.\ Use\ two\ tangent\ theorem.\\\\JK=KL\\\\5x+1=6x-3\\\\6x-5x=1+3\\\\x=4\\\\JK=5x+1=5\times 4+1=21\\\\\\IK=IJ+JK=26+21\\\\IK=47

6 0
3 years ago
Mg+rg=2H, solve for g
lesantik [10]

Answer:

g = 2H/(m + r)

Step-by-step explanation:

mg + rg = 2H

g(m + r) = 2H

(g(m + r))/(m + r) = 2H/(m + r)

g = 2H/(m + r)

3 0
3 years ago
Use the strategy to simplify 4\sqrt(576)<br> Write the prime factorization of the radicand.
Ronch [10]
<h3>Answer:   96</h3>

===================================================

Work Shown:

4\sqrt{576}\\\\4\sqrt{2*2*2*2*2*2*3*3}\\\\4\sqrt{(2*2)*(2*2)*(2*2)*(3*3)}\\\\4\sqrt{(2)^2*(2)^2*(2)^2*(3)^2}\\\\4\sqrt{(2*2*2*3)^2}\\\\4\sqrt{24^2}\\\\4*24\\\\96\\\\

6 0
3 years ago
Read 2 more answers
Help plezzz if u can
xxMikexx [17]

Answer:

60

Step-by-step explanation:

10 / 2 = 5

9 +3 = 12

5 x 2 = 60

5 0
3 years ago
Read 2 more answers
Primitive function for:<br><br> 1. f(x)=4e2x+e−x, sådan att F(0)=2
Free_Kalibri [48]

The primitive function for f(x) = 4e^{2x} + e^{-x} is given by it's indefinite integral.

To calculate it, recall:

\frac{d}{dx}e^{ax}=ae^{ax}

\int c f(x)dx = c\int f(x)dx

Let's begin

\int 4e^{2x}+e^{-x}dx \\4\int e^{2x}dx+ \int e^{-x}dx\\4\frac{e^{2x}}{2}+\frac{e^{-x}}{-1}  + c\\

F(x) = 2e^{2x}-e^{-x} +c

To find the costant, we just need to use the fact that F(0)=2

F(0) = 2 \\4e^{0}+e^{0} + c =2\\5+c =2\\c=-3

Therefore,

\boxed{F(x) = 2e^{2x} - e^{-x} -3 }

6 0
3 years ago
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