a=Δv/Δt=(v-v₀)/t=(46.1-18.5)/2.47=27.6/2.47=11.17 m/s²
d=v₀t+at²/2=18.5*2.47+11.17*2.47²/2=45.69+34.08=79.776 m
Answer:
527 Hz
Solution:
As per the question:
Beat frequency of the player,
Frequency of the tuning fork, f = 523 Hz
Now,
The initial frequency can be calculated as:
when
when
But we know that as the length of the flute increases the frequency decreases
Hence, the initial frequency must be 527 Hz
True i believe because people use this with the wrist and the neck
Answer:
7.15/2 = 3.575m
1.78cos(45.4) = 1.25m
radius = 3.575 + 1.25 = 4.825 m
mg of seat = 10 x 9.8 = 98 N
98/sin(45.4) = 137.64 N
Horizontal force = 137.64cos(45.4) = 96.64 N
Centripetal force = 96.64 N
96.64/10 = 9.6644 = ca
9.6644 x 4.825 = v^2 = 46.63, sq-root = v = 6.83 m/s
(10 + 28.3) x 9.8 = mg = 375.34 N
375.34/sin(45.4) = 527.14 N
Explanation: