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3 years ago

A car velocity changed from 0 m/s to 40m/s in 5 seconds. What is the average acceleration of the car

Physics

2 answers:

aliina [53]3 years ago

6 0

Answer:

8m/s^2

Explanation: Acceleration is the rate of change of velocity per unit of time.

Hence, mathematically

Acceleration = {Velocity(meters/second)}/ time(seconds)

This means that

{40(m/s)}/(5 sec)

=8m/s^2

Morgarella [4.7K]3 years ago

3 0

Answer: 8 m/s2

Explanation: Acceleration is calculated by V1 - V2/ time. 40m/s - 0m/s divided by 5 s = 8 m/s2

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Name the material used to transfer of charges from one body to other

Evgesh-ka [11]

Answer:

conductor

Explanation:

A "conductor" is a material that allows the charges to pass freely from one body to the other. This causes a movement among the electrons and this means that the charge will be passed entirely to the object receiving it. This is also called "conductive material."

Examples of conductors are: copper, aluminum, gold, silver, seawater, etc.

The opposite of conductors are called "insulators." These do not allow the free movement of charges from one object to the other.

Examples of insulators: plastic, rubber, paper, glass, wool, dry air, etc.

6 0

3 years ago

Imagine that you pushed a box, applying a force of 30 Newton’s , over a distance of 5 meters. How much would you do have done ?

kati45 [8]

30 ),which is the force,divided by 5
30÷5=6

7 0

4 years ago

Read 2 more answers

You have a 16-kg suitcase. what work did you do when you have slowly lifted it 0.80 m upward?

Anna71 [15]

The formula is:
Work = Force · Displacement
F = m · g
F = 16 kg · 9.8 m/s² = 156.8 N
and we know that:
d = 0.8 m
W = 156.8 N · 0.8 m = 125.44 J
Answer:
W = 125.44 J.

8 0

4 years ago

A force of 19 newtons is applied on a cart of 2 kilograms, and it experiences a frictional force of 1.7 newtons. What is the acc

Umnica [9.8K]

Frictional force always opposes applied force, so the net force on the cart would have to be 19N - 1.7N. The acceleration can then be solved by using the relation: F = ma. This is shown below:

Net force = 19 - 1.7 = 17.3 N

Acceleration = Force / mass
Acceleration = 17.3 / 2
Acceleration = 8.65 N/m

4 0

3 years ago

Read 2 more answers

If the ball shown in the figure lands in 0.5 s, about what height was it thrown from?

Ede4ka [16]

Answer: 1.22 m

Explanation:

The equation of motion in this situation is:

$y=y_{o}+V_{oy}t-\frac{g}{2}t^{2}$ (1)

Where:

$y=0$ is the final height of the ball

$y_{o}=h$ is the initial height of the ball

$V_{oy}=V_{o}sin(0\°)=0$ is the vertical component of the initial velocity (assuming the ball was thrown vertically and there is no horizontal velocity)