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Ainat [17]
4 years ago
13

Ocean waves pass through two small openings, 20.0 m apart, in a breakwater. You're in a boat 70.0 m from the breakwater and init

ially midway between the openings, but the water is pretty rough. You row 33.0 m parallel to the breakwater and, for the second time, find yourself in relatively calm water. What is the wavelength of the ocean waves ?
Physics
1 answer:
Klio2033 [76]4 years ago
3 0

Answer:

λ = 5.65m

Explanation:

The Path Difference Condition is given as:

δ=(m+\frac{1}{2})\frac{lamda}{n}  ;

where lamda is represent by the symbol (λ) and is the wavelength we are meant to calculate.

m = no of openings which is 2

∴δ= \frac{3*lamda}{2}

n is the index of refraction of the medium in which the wave is traveling

To find δ we have;

δ= \sqrt{70^2+(33+\frac{20}{2})^2 }-\sqrt{70^2+(33-\frac{20}{2})^2 }

δ= \sqrt{4900+(\frac{66+20}{2})^2}-\sqrt{4900+(\frac{66-20}{2})^2}

δ= \sqrt{4900+(\frac{86}{2})^2 }-\sqrt{4900+(\frac{46}{2})^2 }

δ= \sqrt{4900+43^2}-\sqrt{4900+23^2}

δ= \sqrt{4900+1849}-\sqrt{4900+529}

δ= \sqrt{6749}-\sqrt{5429}

δ=  82.15 -73.68

δ= 8.47

Again remember; to calculate the wavelength of the ocean waves; we have:

δ= \frac{3*lamda}{2}

δ= 8.47

8.47 = \frac{3*lamda}{2}

λ = \frac{8.47*2}{3}

λ = 5.65m

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Water enters an ice machine at 55F and leaves as ice at 25F. If the COP of the ice machine is 3.7 during this operation, determi
boyakko [2]

Answer:

The required power is P_i = 0.2692 \ hp

Explanation:

From the question we are told that

   The temperature of the water entering ice machine is T_1 =  55 ^o F

    The temperature of the water leaving is T_2 = 25 ^oF

    The COP of the ice machine is COP= 3.7

    The production rate of an ice  \r m = 15.0 \ lbm /hr

    The energy that needs to removed from each lbm of water at 55 F is E = 169 Btu

Generally the cooling load of the ice machine is mathematically represented as

       \r Q_L =  \r m * E

      \r Q_L =15 * 169

=>  \r Q_L = 2535 \ Btu/h

Generally the COP of the ice machine is mathematically represented as

       COP =  \frac{\r Q_L}{P_i}

Here P_i is the net power  input needed to successfully run the ice machine

So  

     3.7 =  \frac{2535}{P_i}

=>   P_i = 685 \  Btu/h

Converting to horsepower

      P_i = \frac{685}{2545}

=>   P_i = 0.2692 \ hp

     

3 0
3 years ago
Compare and contrast the lithosphere and the asthenosphere(3 different 2 similarities)
worty [1.4K]
Before comparing and contrasting these layers of Earth, we first define what lithosphere and asthenosphere are. 

Lithosphere primarily consists of the outermost layers of the Earth, which are the crust and the uppermost portion of the mantle. Simply, the ground you stepped on is part of earth's lithosphere. On the other hand, asthenosphere comprises of hot and partially molten rock just located at the upper portion of the mantle but just below the lithosphere. Both have similarities and differences, which are as follows:

SIMILARITIES:
- Both are the passageways of earthquakes P-waves (Primary waves) just before it reaches the earth's surface.
- Both are made of the same material (Silicon oxide rocks, which are rich in iron and magnesium)

DIFFERENCES:
- Rocks in lithosphere can bend (it deforms, resulting in fault formations), however, rocks in the asthenosphere, not only bend but also flow (plastic in nature).
- Lithosphere has relatively low temperatures compared to asthenosphere.
- Due to its depth, pressure against rocks in asthenosphere is comparatively higher compared to lithosphere.

8 0
3 years ago
What affect does friction have on motion
satela [25.4K]

Answer: friction reduces the speed during motion

Explanation:

The more the friction, the lesser the speed during motion

3 0
3 years ago
What type of waves move energy forward, but the source moves up and down?
Tresset [83]
Transverse waves is the answer.
Hope I helped if you need anything else ask me
3 0
4 years ago
Calculate the equivalent resistance for both circuits.
Allisa [31]

Answer:

Series equivalent resistance: R_{eq} = 6  \Omega

Parallel equivalent resistance: R_{eq}=14\Omega

Explanation:

The equivalent resistance in series circuit is calculated as

R_{eq} = R_{1} + R_{2}

R_{eq} = 2 + 4

R_{eq} = 6  \Omega

The equivalent resistance in parallel circuit is calculated as

\frac{1}{R_{eq}} = \frac{1}{R_{1}}+\frac{1}{R_{2}}

Which can be simplified to

R_{eq}=\frac{R_{1}\times R_{2}}{R_{1}+R_{2}}

R_{eq}=\frac{21\times 42}{21+42}

R_{eq}=14\Omega

The parallel circuit has the higher equivalent resistance as compared to series circuit.

5 0
4 years ago
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