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melisa1 [442]
4 years ago
15

What is the charge on he helium atom? Explain your reasoning. (A helium atom has two electrons, two protons, and two neutrons.)

Chemistry
1 answer:
gayaneshka [121]4 years ago
3 0

Charge on Helium = 0

'cause, charge = no. of protons-no. of electrons = 2-2 = 0

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The standard emf for the cell using the overall cell reaction below is +2.20 V:
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Answer:

emf generated by cell is 2.32 V

Explanation:

Oxidation: 2Al-6e^{-}\rightarrow 2Al^{3+}

Reduction: 3I_{2}+6e^{-}\rightarrow 6I^{-}

---------------------------------------------------------------------------------

Overall: 2Al+3I_{2}\rightarrow 2Al^{3+}+6I^{-}

Nernst equation for this cell reaction at 25^{0}\textrm{C}-

E_{cell}=E_{cell}^{0}-\frac{0.059}{n}log{[Al^{3+}]^{2}[I^{-}]^{6}}

where n is number of electrons exchanged during cell reaction, E_{cell}^{0} is standard cell emf , E_{cell} is cell emf , [Al^{3+}] is concentration of Al^{3+} and [Cl^{-}] is concentration of Cl^{-}

Plug in all the given values in the above equation -

E_{cell}=2.20-\frac{0.059}{6}log[(4.5\times 10^{-3})^{2}\times (0.15)^{6}]V

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3 0
3 years ago
Which property of a body cannot be changed if a force is applied to it?
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4 years ago
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Which is a characteristic of nuclear fusion but NOT nuclear fission?
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2. A quantity of 1.922g of methanol (CH3OH) was burned in a constant-volume
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Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
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Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
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