3Zn(OH)₂ + 2H₃PO₄ → Zn₃(PO₄)₂ + 6H₂O
Explanation:
To balance this equation, we must understand that in every chemical reaction, the number of atoms is usually conserved.
The total number of atoms on the reactant and product sides must be equal and the same.
Zn(OH)₂ + H₃PO₄ → Zn₃(PO₄)₂ + H₂O
We are are going to use simple, solvable algebraic equations to balance this;
aZn(OH)₂ + bH₃PO₄ → cZn₃(PO₄)₂ + dH₂O
a, b,c and d are the number of coefficient that will balance this equation:
Conserving Zn ; a = 3c
O: 2a + 4b = 8c + d
H: 2a + 3b = 2d
P: b = 2c
let c = 1;
a = 3
b = 2
solving for d;
2d = 2(3) + 3(2)
d = 6
3Zn(OH)₂ + 2H₃PO₄ → Zn₃(PO₄)₂ + 6H₂O
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awnser : 6.02×1023 molcules
Its D for the second energy level, but the first energy level is 2.
If you look at the periodic table you will see the atomic number (the smaller number) which is 3. that identifies how many protons there are. since the lithium is neutral that means there’s a same amount of electrons.
therefore there’s 3 electrons and 3 protons
Answer:
The yield is 16 moles of CO2 per 2 moles of isooctane.
The mass of CO2 is 1.15 billion tonnes
Explanation:
First we set the unbalanced equation:

Now we proceed to balance the equation:

With the equation balanced, we see that the theoretical yield is 16 moles of CO2 per 2 moles of isooctane and we can proceed to make calculations with the following data:

Knowing the different relations between mass, density and molar mass, we have the following results:
