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3 years ago

Complex Numbers Subtract. 7-(-6+3i)-(-3-i)

Mathematics

2 answers:

kykrilka [37]3 years ago

8 0

Answer: 16 - 2i

Explanation:

7-(-6+3i)-(-3-i)
= 7 + 6 - 3i + 3 + i
= 16 - 2i

Savatey [412]3 years ago

6 0

Step 1: 7+6-3i+3+i
Step 2: 16-3i+i
Step 3: simplify: 16-2i

Answer: 16-2i

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Lucas started off with $10.00. he gave away 20% of his money to his sister, and 30% of the remainder of his money to his brother

Korolek [52]

Answer:

5.60

Step-by-step explanation:

20% of 10 = 2 he gave 2 dollars to his sis

2 - 10 = 8 now lucas has 8 dollars

30% of 8 = 2.4 he gave 2.40 dollars to his bro

2.4 - 8 = 5.6

now he has 5 dollars and 60 cents

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3 years ago

"Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an acute triangle.

Contact [7]

A, b, c - the lengths of the sides of the triangle
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$1^o\\5\leq10\leq x\\\\\left\{\begin{array}{ccc}5+10 \ \textgreater \ x\\5^2+10^2 \ \textgreater \ x^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \ 15\\ x^2 \ \textless \ 125\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \ 15\\ x \ \textless \ \sqrt{125}\approx11.1\end{array}\right\\\\\boxed{x=11}\\\\2^o\\5\leq x\leq10\\\\\left\{\begin{array}{ccc}5+x \ \textgreater \ 10\\ 5^2+x^2 \ \textgreater \ 10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x=9}$

$3^o\\x\leq5\leq10\\\\\left\{\begin{array}{ccc}x +5 \ \textgreater \ 10\\ x^2+5^2 \ \textgreater \ 10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x\in\O}\\\\Answer:\boxed{x=9\ or\ x=11}\to your\ answer:\boxed{\boxed{x=11}}$

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3 years ago

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Lerok [7]

Answer:

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Step-by-step explanation:

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2 years ago

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The fraction should be as such.
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