All categories

3 years ago

Help!!! I really need this!!! ASAPPPPP

Mathematics

1 answer:

Korvikt [17]3 years ago

6 0

Answer:

1.5

# of postcards per day

and 9

You might be interested in

The graph of function f(x) = √|x − 5| − 2

Bingel [31]

Answer:

It will look like half of a parabola, rotated 90 degrees, originating at (5, -2), and reflected horizontally.

7 0

3 years ago

Please help I’m so confused

kari74 [83]

1) angle MIG = angle JIH

2) angle PMJ = angle QHG

3) angle MJI

4) 100

6 0

3 years ago

What is the multiplicative rate of change for the exponential function f(x) = 2(5over2 )–x?

azamat

It is 2/5 = 0.4 <span>because of the negative in the exponent.
</span><span>

</span>

6 0

4 years ago

Find f. (Use C for the constant of the first antiderivative and D for the constant of the second antiderivative.)

sashaice [31]

Answer:

$f(x) = x^3 -sinx +Cx+D$

Step-by-step explanation:

Given that:

$f ''(x)= 6x +sinx$

We are given the 2nd derivative of a function f(x) and we need to find f(x) from that.

We will have to integrate it twice to find the value of f(x).

Let us have a look at the basic formula of integration that we will use in the solution:

$1.\ \int {(a\pm b)} \, dx =\int {a} \, dx + \int {b} \, dx \\2.\ \int {x^n} \, dx = \dfrac{x^{n+1}}{n+1}+C\\3.\ \int {sinx} \, dx = -cosx+C\\4.\ \int {cosx} \, dx = sinx+C$

$\int\ {f''(x)} \, dx =\int\ {(6x +sinx)} \, dx \\\Rightarrow \int\ {6x} \, dx + \int\ {sinx} \, dx \\\\\Rightarrow 6\dfrac{x^2}{2} -cosx +C\\\Rightarrow 3{x^2} -cosx +C\\\Rightarrow f'(x)=3{x^2} -cosx +C\\$

Now, integrating it again to find f(x):

$f(x) =\int {f'(x)} \, dx =\int{(3{x^2} -cosx +C)} \, dx \\\Rightarrow \int{3{x^2}} \, dx -\int{cosx} \, dx +\int{C} \, dx\\\Rightarrow 3\times \dfrac{x^3}{3} -sinx +Cx+D\\\Rightarrow x^3 -sinx +Cx+D\\\\\therefore f(x) = x^3 -sinx +Cx+D$

5 0

4 years ago

Help as soon as possible thanks

frutty [35]

6x11=66ft
3x14=42ft

Add the answers together
42+66
= 108 squared feet

5 0

2 years ago