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zhuklara [117]
3 years ago
9

Use the diagram below to determine the height of the flagpole.

Mathematics
1 answer:
Shtirlitz [24]3 years ago
6 0

Answer:

Height of flagpole= 12ft

Scale factor from stick to flagpole: 3:1

Scale Factor from flagpole to stick: 1:3

Step-by-step explanation:

ratio from stick to shadow = ratio from flagpole to shadow

so 4:2.5

we can assume 4(3):2.5(3)

which is 12:7.5

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The table below shows the number of tickets sold per
andrew11 [14]

Answer:

102 tickets

Step-by-step explanation:

start by adding

Mon 198

Tues 96

We'd 204

then you would get 498 and max people that can fit in the gym is 600 so then you would subtract 600-498 and get 102 so the maximum amount of tickets they can sell on Thursday is 102 tickets

4 0
3 years ago
8c^(2)+6c-2c^(2)-5c
iren [92.7K]

Answer:

6c^2 + c

Step-by-step explanation:

8^2 - 2c^2= 6c^2

6c-5c = c

6 0
3 years ago
-4x + 5 > -5 please help me
masya89 [10]

Answer:

x<5/2

Step-by-step explanation:

hope this helps :)

5 0
3 years ago
Read 2 more answers
...............what is (9x^2-3)^6
Lelu [443]
Step 1. Factor out the common term 3

(3(3 x^{2}-1)^{6}

Step 2. Use <span>Multiplication Distributive Property: </span>(xy)^{a} = x^{a}  y^{a}
<span>
</span>3^{6}(3 x^{2}-1)^{6}
<span>
Step 3. Simplify </span>3^{6} to 729

729(3 x^{2}-1)^{6}

Done!
8 0
4 years ago
Cos theta if tan theta equals 2/5
Vanyuwa [196]
\bf tan(\theta)=\cfrac{opposite}{adjacent}\qquad tan(\theta)=\cfrac{2}{5}\cfrac{\impliedby opposite}{\impliedby adjacent}\\\\&#10;-----------------------------\\\\&#10;\textit{using the pythagorean theorem then}\\\\&#10;c^2=a^2+b^2\implies c=\pm \sqrt{a^2+b^2}\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite&#10;\end{cases}&#10;\\\\\\&#10;\textit{recall that }cos(\theta)=\cfrac{adjacent}{hypotenuse}

so.. .to get the cosine from that, all we need is the "hypotenuse" or radius in that angle

now.... keep in mind that, there are two likely quadrants where the opposite and adjacent sides, or x and y, are both positive, or both negative

I and II quadrants, so on those two quadrants, the tangent will be positive, since both numerator an denominator have the same sign

but I gather in this case, it may be assumed is the first quadrant, namely, that is 2/5 as opposed to -2/-5, so the adjacent side is positive
5 0
4 years ago
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