Answer:
The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance
Null hypothesis is accepted at 0.05 level of significance
A company has developed a training procedure is significantly improve scores
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given  sample mean (x⁻ )  = 517
sample standard deviation (s) =90
Mean of the Population (μ) =500
<em>Null Hypothesis :- H₀ :  </em> (μ) =500
Alternative Hypothesis : H₁ :  μ ≠ 500
<u><em>Step(ii)</em></u>:-
Test statistic 
                          
                         
                         t  =   1.717
<em>Level of significance</em>
                       ∝ = 0.05
                     t₀.₀₅ = 1.6604
The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance
<u><em>Conclusion</em></u>:-
Null hypothesis is accepted at 0.05 level of significance
A company has developed a training procedure is significantly improve scores