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max2010maxim [7]
3 years ago
7

What is 8x - 7 + 12x after being simplified?

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
8 0
20x should be your answer
Vinvika [58]3 years ago
3 0

Answer:

8x - 7 + 12x after being simplified would be 20x - 7

Step-by-step explanation:

Add 8x and 12<em>x</em>.

8 + 12 = 20<em>x</em>

20<em>x</em> - 7 would be your answer.

Hope this helps!

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The marked price of a water cooler is $ 500. The shopkeeper offers an off-season discount of 15% on it. Find the discount.
Fittoniya [83]

Answer:

75 dollars

Step-by-step explanation:

You know that 500=100%, so we can set up the following

15%(500/100%) = 75

so the discount 75 dollars

5 0
3 years ago
What is the range of function gif g(x) = -2/(x) + 1
Zina [86]

The function g(x) is a rational function, and none of the options represent the range of the function g(x)

<h3>How to determine the range of the function?</h3>

The function is given as:

g(x) = -2/x + 1

The above function is undefined at point x = 0.

This is so because -2/x is undefined.

So, we have:

g(0) = -undefined + 1

g(0) = undefined

This means that the range of the function is:

(-infinity, 1) and (1, infinity)

None of the options represent the range of the function g(x)

Read more about range at:

brainly.com/question/10197594

#SPJ1

5 0
2 years ago
Find the area of the shaded region. Round to the nearest tenth.
AURORKA [14]

Answer:

3.5 square cm

Step-by-step explanation:

Area \: of \: both \: squares  \\ =  {2}^{2}  +  {3}^{2}  \\  = 4 + 9 \\  = 13 \:  {cm}^{2}  \\  \\ Area \: of \: both \: right \:  \triangle s \\  =  \frac{1}{2}  \times (2 + 3) \times 2 + \frac{1}{2}  \times3 \times 3 \\  = 5 \times 1+ 1.5 \times 3 \\  = 5 + 4.5 \\  = 9.5 \:  {cm}^{2}  \\  \\ Area \: of \:shaded \: region \\  = Area \: of \: both \: squares\\ - Area \: of \: both \: right \:  \triangle s \\  = 13 - 9.5 \\   \purple { \boxed{ \bold{Area \: of \:shaded \: region = 3.5 \:  {cm}^{2} }}}

7 0
3 years ago
Was Burns $400 for 40 hours of work is a ratio table to determine how much you earn for six hours of work
Alina [70]
You would earn 60 for 6 hours of work.

7 0
3 years ago
Find the exact length of the curve. 36y2 = (x2 − 4)3, 5 ≤ x ≤ 9, y ≥ 0
IrinaK [193]
We are looking for the length of a curve, also known as the arc length. Before we get to the formula for arc length, it would help if we re-wrote the equation in y = form.

We are given: 36 y^{2} =( x^{2} -4)^3
We divide by 36 and take the root of both sides to obtain: y = \sqrt{ \frac{( x^{2} -4)^3}{36} }

Note that the square root can be written as an exponent of 1/2 and so we can further simplify the above to obtain: y =  \frac{( x^{2} -4)^{3/2}}{6} }=( \frac{1}{6} )(x^{2} -4)^{3/2}}

Let's leave that for the moment and look at the formula for arc length. The formula is L= \int\limits^c_d {ds} where ds is defined differently for equations in rectangular form (which is what we have), polar form or parametric form.

Rectangular form is an equation using x and y where one variable is defined in terms of the other. We have y in terms of x. For this, we define ds as follows: ds= \sqrt{1+( \frac{dy}{dx})^2 } dx

As a note for a function x in terms of y simply switch each dx in the above to dy and vice versa.

As you can see from the formula we need to find dy/dx and square it. Let's do that now.

We can use the chain rule: bring down the 3/2, keep the parenthesis, raise it to the 3/2 - 1 and then take the derivative of what's inside (here x^2-4). More formally, we can let u=x^{2} -4 and then consider the derivative of u^{3/2}du. Either way, we obtain,

\frac{dy}{dx}=( \frac{1}{6})( x^{2} -4)^{1/2}(2x)=( \frac{x}{2})( x^{2} -4)^{1/2}

Looking at the formula for ds you see that dy/dx is squared so let's square the dy/dx we just found.
( \frac{dy}{dx}^2)=( \frac{x^2}{4})( x^{2} -4)= \frac{x^4-4 x^{2} }{4}

This means that in our case:
ds= \sqrt{1+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{4}{4}+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{x^4-4 x^{2}+4 }{4}} dx
ds= \sqrt{\frac{( x^{2} -2)^2 }{4}} dx
ds=  \frac{x^2-2}{2}dx =( \frac{1}{2} x^{2} -1)dx

Recall, the formula for arc length: L= \int\limits^c_d {ds}
Here, the limits of integration are given by 5 and 9 from the initial problem (the values of x over which we are computing the length of the curve). Putting it all together we have:

L= \int\limits^9_5 { \frac{1}{2} x^{2} -1 } \, dx = (\frac{1}{2}) ( \frac{x^3}{3}) -x evaluated from 9 to 5 (I cannot seem to get the notation here but usually it is a straight line with the 9 up top and the 5 on the bottom -- just like the integral with the 9 and 5 but a straight line instead). This means we plug 9 into the expression and from that subtract what we get when we plug 5 into the expression.

That is, [(\frac{1}{2}) ( \frac{9^3}{3}) -9]-([(\frac{1}{2}) ( \frac{5^3}{3}) -5]=( \frac{9^3}{6}-9)-( \frac{5^3}{6}-5})=\frac{290}{3}


8 0
3 years ago
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