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yulyashka [42]
3 years ago
11

Multiply and simplify into lowest form

Mathematics
1 answer:
Anni [7]3 years ago
6 0
Here is an answer on the picture I do my best

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Solve with subsitution <br> y-3x=2<br> y=-2x-8 <br> show ur work HURRY PLSS
IRINA_888 [86]

Answer:

y-3x=2......1

y=-2x-8 ......2

substituting value of y in equation 1

-2x-8-3x=2

-5x=2+8

x=10/-5=-2

substituting value of x in equation 1

y-3×(-2)=2

y+6=2

y=2-6=-4

x=-2

y=-4

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Saturday, nola bowled 3 games in her bowling league. she had a mean score of 115. the score of her first game was 110. the score
Elina [12.6K]
110+90+145=345
345 divided by 3=115

so the score of her third game was 145 points.
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If r = 10 units and x = 14 units, then what is the volume of the cylinder shown above?
Agata [3.3K]

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An automobile manufacturer has given its car a 46.7 miles/gallon (MPG) rating. An independent testing firm has been contracted t
erastova [34]

Answer:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

The p value would be given by:

p_v =2*P(z  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

Step-by-step explanation:

Information given

\bar X=46.5 represent the mean

\sigma=1.1 represent the population standard deviation

n=150 sample size  

\mu_o =46.7 represent the value to verify

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean for this case is 46.7, the system of hypothesis would be:  

Null hypothesis:\mu = 46.7  

Alternative hypothesis:\mu \neq 46.7  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Replacing we got:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

The p value would be given by:

p_v =2*P(z  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

7 0
3 years ago
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