Question

The function y=−16x2+v0x models Lindy's height in feet above a trampoline x seconds after she jumps straight up. In the equation of the function, v0 is her initial velocity in feet per second. Lindy lands back on the trampoline 1 second after she jumps.

Answer 1

Answer:

The initial velocity of Lindy was 16 ft/s

Step-by-step explanation:

Given: $y=-16x^2+v_0x$

It is function models of Lindy's Height in feet above a trampoline x seconds after she jumps straight up.

In the equation of the function

$v_0$ is initial velocity in feet per second.

We need to find the initial speed of Lindy

If She lands back on the trampoline after 1 seconds.

It means y must be zero because she lands back on trampoline.

At x=1, y must be 0

$0=-16(1)^2 + v_0(1)$

$v_0=16$

Hence, The initial velocity of Lindy was 16 ft/s

Answer 2

Ok  so when she lands  her height is 0  and x = 1 second so we can write

-16x^2 v0x  = 0 
plug in x = 1

-16(1)^2 + v0 = 0
v0 = 16*1 = 16

so initial velocity = 16 ft/second