For a function, if it has an inverse function, keep in mind that, the "domain of the original, is the range of the inverse, and the range of the original, is the domain of the inverse", what the dickens does that mean?

well, it means the values for "x" and f(x), on the inverse, are the same values, but swapped up, therefore

$\bf \stackrel{original~function}{\begin{array}{ccll}
x&f(x)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
-4&-2\\
-2&-1\\
0&0\\
2&1\\
4&2
\end{array}}\qquad \qquad \qquad 
\stackrel{inverse~function}{\begin{array}{ccll}
x&f(x)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
-2&-4\\
-1&-2\\
0&0\\
1&2\\
2&4
\end{array}}$

7 0

2 years ago

A matatu carries 14 passengers per trip. In

PilotLPTM [1.2K]

Answer:

"23,520"

Step-by-step explanation:

one trip: 14 passengers

one day: 3 trips

passengers: 80

80x14= 1,120

1,120x3= 3,360

3,360x7= 23,520

6 0

2 years ago

What do you predict the solution for the system 5x-6y=7 and 6x-7y=8 will be ?<br>

Alenkinab [10]

System of Linear Equations entered :

[1] 5x - 6y = 7
[2] 6x - 7y = 8
Graphic Representation of the Equations :

-6y + 5x = 7 -7y + 6x = 8

Solve equation [2] for the variable x

[2] 6x = 7y + 8

[2] x = 7y/6 + 4/3
// Plug this in for variable x in equation [1]

[1] 5•(7y/6+4/3) - 6y = 7
[1] - y/6 = 1/3
[1] - y = 2
// Solve equation [1] for the variable y

[1] y = - 2
// By now we know this much :

x = 7y/6+4/3
y = -2
// Use the y value to solve for x

x = (7/6)(-2)+4/3 = -1

8 0

2 years ago