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valkas [14]
3 years ago
12

jessica has a jewelry box with a base of 18 square inches. the height is 7 inches. what is the volume of her jewelry box?

Mathematics
2 answers:
ozzi3 years ago
6 0
Assuming it is a right rectangular prism, the volume is 126 sq. in.

V = area of base * height = 18 * 7 = 126
marissa [1.9K]3 years ago
5 0

Volume is the amount of material any box can hold.It is expressed in cubic units.

Volume of any figure is base area times the height.

Jessica jewelry box was having a base of 18  inches and base area of 18 square inches.

Volume of Jewelry box= base area x height

Volume of box=18x7=126 cubic inches.

Jessica Jewelry box has a volume of 126 cubic inches.

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56/(7-9)^3-25/23-5*4
meriva
I got -28.08695652. It doesn't repeat nor does it terminate
4 0
3 years ago
The following prices, in dollars, of 7.5-cubic-foot refrigerators were recorded from a random sample. 314 305 344 283 285 310​ 3
Mariana [72]

Answer:

t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109      

The degrees of freedom are given by:

df=n-1=10-1=9  

And the p value would be given by:

p_v =P(t_{9}>1.109)=0.148  

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

Step-by-step explanation:

Information given

314 305 344 283 285 310​ 383​ 285​ 300​ 300

We can calculate the sample mean and deviation with the following formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}

\bar X=310.9 represent the sample mean      

s=31.09 represent the standard deviation for the sample      

n=10 sample size      

\mu_o =300 represent the value to test

\alpha=0.05 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to verify if the true mean is greater than 300, the system of hypothesis would be:      

Null hypothesis:\mu \leq 300      

Alternative hypothesis:\mu > 300      

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

Replacing the info given we got:

t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109      

The degrees of freedom are given by:

df=n-1=10-1=9  

And the p value would be given by:

p_v =P(t_{9}>1.109)=0.148  

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

6 0
3 years ago
PLEASE HELP 20 POINTS!! QUESTION IS AN IMAGE
prisoha [69]

Okay, so first off, if you need to graph anything, I suggest Desmos, it's a website with an online graphing calculator. It saved my life for highschool geometry.

Now, to answer your question, your y-intercept is going to be at point (0,2). Your x-intercepts are going to be at points (-2,0) and (-4,0). Your point is at (-3,-1). And then your lines simply extend from there.

Hope this isn't too late to be helpful, good luck with your assignments.

5 0
2 years ago
What is the value of x?
Akimi4 [234]
(2x + 2) = (3x + -52)

Reorder the terms:
(2 + 2x) = (3x + -52)

Remove parenthesis around (2 + 2x)
2 + 2x = (3x + -52)

Reorder the terms:
2 + 2x = (-52 + 3x)

Remove parenthesis around (-52 + 3x)
2 + 2x = -52 + 3x

Solving
2 + 2x = -52 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
2 + 2x + -3x = -52 + 3x + -3x

Combine like terms: 2x + -3x = -1x
2 + -1x = -52 + 3x + -3x

Combine like terms: 3x + -3x = 0
2 + -1x = -52 + 0
2 + -1x = -52

Add '-2' to each side of the equation.
2 + -2 + -1x = -52 + -2

Combine like terms: 2 + -2 = 0
0 + -1x = -52 + -2
-1x = -52 + -2

Combine like terms: -52 + -2 = -54
-1x = -54

Divide each side by '-1'.
x = 54

Simplifying
x = 54
4 0
3 years ago
I am have trouble with these x-intercepts. Please help me.​
kotegsom [21]

Answer:

  1. x=8, x=2
  2. no solution
  3. no solution

Step-by-step explanation:

For the equation ...

  y = a(x -h)² +k

you can find the x-intercepts by setting y=0 and solving for x.

  0 = a(x -h)² +k

  -k = a(x -h)² . . . . . . subtract k

  -k/a = (x -h)² . . . . . divide by a

  ±√(-k/a) = x -h . . . . take the square root

  h ± √(-k/a) = x . . . . add h . . . . this is the general solution

__

So, for each of your problems, fill in the corresponding numbers and do the arithmetic. If (-k/a) is a negative number, the square root gives imaginary values, so there is "no solution".

1.  x = 5 ± √9 = {5 -3, 5 +3} = {2, 8} . . . . the x-intercepts are 2 and 8

2.  x = -3 ± √(-2) . . . . . . no solution; the roots are complex

3.  x = 5 ± √(-8/4) . . . . . no solution; the roots are complex

7 0
3 years ago
Read 2 more answers
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