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3 years ago

What is the height of an equilateral triangle with all sides equal to 8

Mathematics

2 answers:

zysi [14]3 years ago

7 0

Drop a perpendicular line from a vertex to opposite side

This forms 2 triangles whose side are in the ratio 2:1:sqrt3

The 2 is equivalent to 8 so the height is sqrt3/2 * 8 = 4 sqrt3 units (answer)

( or 6.93 units to nearest hundredth.)

vitfil [10]3 years ago

3 0

an equilateral triangle has a square root height if 3 so I'm guessing if you multiply square root of 3 times 8

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Solve for x and graph the solution on the number line 15 > 2x – 9 > -23

Monica [59]

The answer is 12>x>-7

Step-by-step explanation:

it's first divided into 2 parts

1 . 15 > 2x - 9

2. 2x - 9 > -23

Then solve them individually.

let's do it,

First half

15 > 2x - 9

15+9 > 2x

24 > 2x

24/2 > x

12>x

Second half

2x-9>-23

2x>-23+9

2x>-14

x>-14/2

x>-7

Joining of the two halves

We have :

12>x>-7

8 0

3 years ago

Shanika makes 2,800 milliliter so of chicken soup for a dinner party.she needs 3.5 liters. how many more milliliter so does shan

WINSTONCH [101]

1L=1000mL
2800 mL=2.8L
If she needs 3.5 L, she currently has 2.8L,
so 3.5-2.8=0.7 L more or .7x1000=700 more mL

5 0

3 years ago

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e

Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in $\mu g/mL$

$C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})$

Thus, we are given the time interval [0,12] for t.

We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

$\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})$

Equating the first derivative to zero, we get,

$\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0$

Solving, we get,

$8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2$