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3 years ago

What is the height of an equilateral triangle with all sides equal to 8

Mathematics

2 answers:

zysi [14]3 years ago

7 0

Drop a perpendicular line from a vertex to opposite side

This forms 2 triangles whose side are in the ratio 2:1:sqrt3

The 2 is equivalent to 8 so the height is sqrt3/2 * 8 = 4 sqrt3 units (answer)

( or 6.93 units to nearest hundredth.)

vitfil [10]3 years ago

3 0

an equilateral triangle has a square root height if 3 so I'm guessing if you multiply square root of 3 times 8

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Meaghan and Lily are dividing 43.61 by 7. Meaghan says that the first digit of the quotient is in the ones place. Lily says it i

Ivahew [28]

Answer: Meaghan is right.

Step-by-step explanation:

For a number like:

123.45

the tens place would be the "2" (second number at the left of the decimal point)

The ones place would be the "3" (first number at the left of the decimal point)

Let's suppose that Lily is correct.

Then the quotient of:

43.61/7

Will be a number with two digits in the left of the decimal point.

The smallest number that meets this condition, is the number 10.

Then let's see:

7*10 = 70

then:

70/7 = 10

and:

43.61 < 70

(70 is larger than 43.61)

then:

43.61/7 < 70/7 = 10

Then:

(43.61/7) < 10

This means that our quotient is smaller than 10, then the first digit of the quotient can not be on the tens place.

Then Meaghan is the correct one.

We also could perform the quotient to find:

43.61/7 = 6.23

So yes, Meaghan is correct.

5 0

2 years ago

A bag contains 3 red, 5 yellow, and 7 purple marbles. Find the probability of drawing a purple marble followed by a red marble.

jeka57 [31]

Answer:

unsimplified : $\frac{21}{225} or simplified: \: \frac{7}{75}$

Step-by-step explanation:

Work out : Look above at image.

3 0

3 years ago

Reflect quadrilateral CJKM across the y-axis. Find the location of K'.

Montano1993 [528]

$K(1,4)\rightarrow K^{\prime}(-1,4)$

Explanation

Step 1

find the coordinate of every point of the quadrilateral

C(-3,1)

J(0,1)

K(1,4)

M(4,-2)

Step 2

When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite (its sign is changed).

$(x,y)\rightarrow reflect\text{ across y -Ax is}\rightarrow(-x,y)$

therefore

$\begin{gathered} C\mleft(-3,1\mright)\rightarrow C^{\prime}(3,1) \\ J\mleft(0,1\mright)\rightarrow J^{\prime}(0,1) \\ K\mleft(1,4\mright)\rightarrow K^{\prime}(-1,4) \\ M(4,-2)\rightarrow M^{\prime}(-4,-2) \end{gathered}$

so, the answer is