Question down below

Mathematics

1 answer:

Nitella [24]3 years ago

8 0

Answer:

angle s is 22 degrees

Step-by-step explanation:

hope this helped

You might be interested in

Round it to the nearest hundredth if necessary 75kg=? Lb

umka2103 [35]

75kg is equal to 165.347 lbs.
You can find these kinds of questions easily answered with the help of google :)

5 0

3 years ago

A bowl contains blueberries and strawberries. There are a total of 48 berries in the bowl. The ratio of blueberries to strawberr

Dvinal [7]

Answer:

a. 36 blueberries and 12 strawberries

b. 16 blueberries and 4 strawberries

Step-by-step explanation:

The computation of each berry in the bowl is shown below;

a. Total 48 berries

The Ratio of blueberries to strawberries is 9:3

So, the blueberries is = 48 × 9 ÷ (9 + 3) = 36

And, the strawberries is = 48 × 3 ÷ (9 + 3) = 12

b. Total 20 berries

The Ratio of blueberries to strawberries is 4:1

So, the blueberries is = 20 × 4 ÷ (4 + 1) = 16

And, the strawberries is = 20 × 1 ÷ (4 + 1) = 4

6 0

2 years ago

A caterer charges $500 plus $30 per guest to cater a wedding. Walt and Traci don't want to spend more than $8000 on catering. Wr

Irina-Kira [14]

500 + 30g ≤ 8000
30g ≤ 7500
g ≤ 250

3 0

2 years ago

Read 2 more answers

Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )

Zina [86]

Answer:

$\purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

Step-by-step explanation:

$\cos( \alpha ) = \frac{ \sqrt{6} }{6} = \frac{1}{ \sqrt{6} } \\ \\ \therefore \: \sin( \alpha ) = \sqrt{1 - { \cos}^{2} ( \alpha ) } \\ \\ = \sqrt{1 - \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} } \\ \\ = \sqrt{1 - {\frac{1}{ {6} }}} \\ \\ = \sqrt{ {\frac{6 - 1}{ {6} }}} \\ \\ \red{\sin( \alpha ) = \sqrt{ { \frac{5}{ {6} }}} } \\ \\ \tan( \alpha ) = \frac{\sin( \alpha ) }{\cos( \alpha ) } = \sqrt{5} \\ \\ \sin( \beta ) = \frac{ \sqrt{2} }{4} \\ \\ \implies \: \cos( \beta ) = \sqrt{ \frac{7}{8} } \\ \\ \tan( \beta ) = \frac{\sin( \beta ) }{\cos( \beta ) } = \frac{1}{ \sqrt{7} } \\ \\ \tan( \alpha - \beta ) = \frac{ \tan \alpha - \tan \beta }{1 + \tan \alpha . \tan \beta} \\ \\ = \frac{ \sqrt{5} - \frac{1}{ \sqrt{7} } }{1 + \sqrt{5} . \frac{1}{ \sqrt{7} } } \\ \\ = \frac{ \sqrt{35} - 1 }{ \sqrt{7} + \sqrt{5} } \\ \\ \purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$