Hello please help on number 3

The probability that a randomly selected 3-year-old male chipmunk will live to be 4 years old is 0.96516.

mezya [45]

Using the binomial distribution, it is found that there is a:

a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

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For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

0.96516 probability of a chipmunk living through the year, thus $p = 0.96516$

Item a:

Two is P(X = 2) when n = 2, thus:

$P(X = 2) = C_{2,2}(0.96516)^2(1-0.96516)^{0} = 0.9315$

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

Item b:

Six is P(X = 6) when n = 6, then:

$P(X = 6) = C_{6,6}(0.96516)^6(1-0.96516)^{0} = 0.80834$

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

Item c:

At least one not living is:

$P(X < 6) = 1 - P(X = 6) = 1 - 0.80834 = 0.19166$

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

A similar problem is given at brainly.com/question/24756209

6 0

2 years ago

Which visualization tool is more helpful for detecting outliers in data? Select one: a. scatter plot b. histogram c. Boxplot

Tpy6a [65]

Answer:

(A) Scatterplot

Step-by-step explanation:

The most helpful visualization to spot outliers would be a scatterplot.

When collecting data on a scatterplot, you can see how the results are similar and which areas have the most answers and such.

There can be multiply outliers on a scatterplot, and they stand out because while most answers will be clumped together, the outliers will not.

7 0

3 years ago

Consider the following function. f(x) = |x − 9| Find the derivative from the left at x = 9. If it does not exist, enter NONE. -1

nydimaria [60]

Answer with Step-by-step explanation:

We are given that

$f(x)=\mid x-9\mid$

$f(x)=-(x-9)$ when x<9

$f(x)=x-9$ when $x\geq 9$

LHD

$\lim_{x\rightarrow 9-}f'(x)$

= $-\lim_{x\rightarrow 9-}(x-9)=-1$

RHD

$\lim_{x\rightarrow 9+}f'(x)$

$=\lim_{x\rightarrow 9+}(x-9)=1$

$LHD\neq RHD$

Hence, the function is not differentiable at x=9

8 0

2 years ago

Annita, Gary, and Tara all run races. Annita has 7 less than 4 times the number of race medals as Tara. Gary has 13 more than 2

harkovskaia [24]

Answer:

4 t - 7 = 2 t+ 13 is the required equation.

The number of race medals Tara has is t = 20 medals.

Step-by-step explanation:

Let the number of medals Tara has = t medals

So, the number of medal Anita has = 4( Medals of Tara) - 7

= 4t - 7

And the number of medals Gary has = 2 times (Medals of Tara) + 13

= 2(t) + 13 = 2t + 13

Now, Annita and Gary has same number of medals.

⇒ 4t - 7 = 2t+ 13

or, 4t - 2t = 7 + 13

⇒ 2t = 20

⇒ t = 20/2 = 10

or t = 10

Hence, the number of race medals Tara has is t = 20 medals

6 0

3 years ago

5c squared- d squared+3/2c - 4d...c= -1. d= -4

riadik2000 [5.3K]

For this case we have the following expression:

$5c ^ 2-d ^ 2 + \frac {3} {2} c-4d$

We must find the value of the expression when:

$c = -1\\d = -4$

Substituting we have:

$5 (-1) ^ 2 - (- 4) ^ 2 + \frac {3} {2} (- 1) -4 (-4) =\\5 (1) -16- \frac {3} {2} + 16 =\\5-16- \frac {3} {2} + 16 =\\-11- \frac {3} {2} + 16 =\\- \frac {25} {2} + 16 =\\\frac {-25 + 32} {2} =\\\frac {7} {2}$

Finally, the value of the expression is:

$\frac {7} {2}$

ANswer:

$\frac {7} {2}$

5 0

3 years ago