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anzhelika [568]
3 years ago
10

Hello please help on number 3

Mathematics
1 answer:
padilas [110]3 years ago
3 0

18 + 22 + 23 + 24 + 25 + 26 + 30= 168

168/7= 24

the missing number is 24


Good Luck! XD

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Find the volume of the region bounded above by the paraboloid z equals 3 x squared plus y squared and below by the square R: min
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Answer:

V=5.333cubit unit

Step-by-step explanation:

this problem question, we are required to evaluate the volume of the region bounded by the paraboloid z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1

The question can be interpreted as z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1 and we are told to evaluate the volume of the region bounded by the given paraboloid z

The volume V of integral evaluated along the limits of x and y for the 2-D figure, can be evaluated using the expression below

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CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLATION:

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3 years ago
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r-ruslan [8.4K]

Option A

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8 0
2 years ago
-4 + 4d + 17 = 33<br> D = ?
cricket20 [7]

Answer:

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Step-by-step explanation:

I think it is 3, because...

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2 years ago
What’s the answer for 3n-6=33 I have to solve for n
dezoksy [38]

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7 0
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Read 2 more answers
Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract
anyanavicka [17]

Answer:

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8

Step-by-step explanation:

The sum you are trying to understand is this.

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}

Remember that in general when you have a geometric series  

\sum\limits_{n = 0}^{\infty} a*r^n you have that

\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}      and that equality is true as long as     |r| < 1.

Therefore here we have

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n        and   \big|\frac{-1}{15} \big| = \frac{1}{15} < 1

Therefore we can use the formula and

\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n =  \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16  = 15/8

5 0
3 years ago
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