Find the volume of the region bounded above by the paraboloid z equals 3 x squared plus y squared and below by the square R: min
us 1 less than or equals x less than or equals 1 comma negative 1 less than or equals y less than or equals 1.
1 answer:
Answer:
V=5.333cubit unit
Step-by-step explanation:
this problem question, we are required to evaluate the volume of the region bounded by the paraboloid z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1
The question can be interpreted as z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1 and we are told to evaluate the volume of the region bounded by the given paraboloid z
The volume V of integral evaluated along the limits of x and y for the 2-D figure, can be evaluated using the expression below
V = ∫∫ f(x, y) dx dy then we can now substitute and integrate accordingly.
CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLATION:
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Answer:
K(x) = ( curvature function)
Step-by-step explanation:
considering the Given function
F(x) =
first Determine the value of F'(x)
F'(x) =
F'(x) = -10x
next we Determine the value of F"(x)
F"(x) =
F" (x) = -10
To find the curvature function we have to insert the values above into the given formula
K(x)
K(x) = ( curvature function)