Find the volume of the region bounded above by the paraboloid z equals 3 x squared plus y squared and below by the square R: min
us 1 less than or equals x less than or equals 1 comma negative 1 less than or equals y less than or equals 1.
1 answer:
Answer:
V=5.333cubit unit
Step-by-step explanation:
this problem question, we are required to evaluate the volume of the region bounded by the paraboloid z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1
The question can be interpreted as z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1 and we are told to evaluate the volume of the region bounded by the given paraboloid z
The volume V of integral evaluated along the limits of x and y for the 2-D figure, can be evaluated using the expression below
V = ∫∫ f(x, y) dx dy then we can now substitute and integrate accordingly.
CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLATION:
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Step-by-step explanation:
We know that Kate runs 2/3 of a mile on Mondays, Wednesdays and Thursdays. She runs 4/5 of a mile on Tuesday and Fridays. We calculate how many miles does Kate run during the week.
Therefore, we get
Therefore, we conclute that Kate run 1 mile and 7/15 of a mile for the week.
The correct description of the graph:
<em>"One curve opens up and to the right in quadrant 1, and the other curve down and to the left in </em><em>quadrants </em><em>2, 1, and 4."</em>
<h3>Which graph is the graph of the given functions?</h3>
Here we have the function:
The graph of this function can be seen below:
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Then the correct option is:
<em>"One curve opens up and to the right in </em><em>quadrant </em><em>1, and the other curve down and to the left in </em><em>quadrants </em><em>2, 1, and 4."</em>
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If you want to learn more about rational functions:
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