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Yanka [14]
3 years ago
10

this is due in less the 30 minutes and this is my last question on the assignment please help and show work. will give brainlies

t

Mathematics
2 answers:
Oduvanchick [21]3 years ago
5 0

Answer:

22,100

Step-by-step explanation:

valina [46]3 years ago
5 0

Answer:

the answer in 18,300

Step-by-step explanation:

2 x 3 5/8= 7 1/4

7 1/4 +1 9/10= 9 3/20

9 3/20 / 2= 18 3/10

18 3/10 x 1000=18,300

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Help me please idk how to do this
Tems11 [23]

Answer: your answer would be B

- 5 over 9

Step-by-step explanation:

3 0
3 years ago
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What is the shape of the cross-section formed when a plane containing line AC and line EH intersects this cube? What is the area
liq [111]

Answer:

Area of given figure = 96 unit²

Step-by-step explanation:

Given:

Length of shape = 4 unit

Width of shape = 4 unit

Height of shape = 4 unit

Find:

Area of given figure

Computation:

All side of figure all equal

So,

Given figure is a cube

Number of faces of cube = 6

Area of base = side x side

Area of base = 4 x 4

Area of base = 16 unit²

Area of given figure = Area of base x Number of faces of cube

Area of given figure = 16 x 6

Area of given figure = 96 unit²

8 0
2 years ago
Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len
Rama09 [41]

The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is

\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt

In this case, we have

<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> )   ==>   d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )

<em>y(t)</em> = 5 - 2<em>t</em>   ==>   d<em>y</em>/d<em>t</em> = -2

and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then

\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt

=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt

=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt

=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt

=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}

5 0
2 years ago
Helpppp Plsssss Asap!! Show your work​
satela [25.4K]

Answer:

Step-by-step explanation:

The anwser is C

the inverse of 5x is x/5 and the inverse of +4 is -4 so the answer would be x-4/5

8 0
3 years ago
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Ping's Ice Cream Palace offers a special sundae that contains over 2 kilograms of ice cream plus any number of toppings. Write a
hjlf

Let "x" represent the weight of the toppings. We know that we can have any number of toppings. This means that one may ask for no toppings at all too.

Now, we have been told that "S" is the weight of the special sundae in kilograms. This definitely included the "mandatory" 2 kilograms of ice cream. Therefore, S will be at-least equal to 2.

Thus, the inequality that describes S, the weight of the special sundae in kilograms at Ping's Ice Cream Palace is given as:

S\geq 2+x kilograms.

It can be seen that as x increases, S increases too and if an order does not want any toppings in it then the weight of the special sundae will be a minimum of 2 kg which is the weight of the ice cream.

7 0
3 years ago
Read 2 more answers
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