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vlabodo [156]
4 years ago
6

Please help!!! 20 points

Mathematics
1 answer:
V125BC [204]4 years ago
6 0

Answer:

A) x = (-8log(6)-2log(17))/(-2log(17)+log(6))

Step-by-step explanation:

Taking the logarithm of the equation, you have ...

(x+8)log(6) = (2x-2)log(17)

Subtracting the right side from the equation gives ...

x(log(6) -2log(17)) +8log(6)+2log(17) = 0

Subtracting the constant and dividing by the coefficient of x gives ...

x = -(8log(6) +2log(17))/(log(6) -2log(17)) . . . . . matches selection A

___

You don't need to work out the whole solution to determine the correct answer choice. Once you take the initial log, you find that the x-coefficient includes a multiplier of 2log(17). This term only appears in the denominator of choice A. (The value of x will be found after dividing by the x-coefficient, so you know this must show up in the denominator of the answer.)

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ohaa [14]

Answer:

x = 23

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Step-by-step explanation:

70 and  3x+1 are alternate exterior angles and that means they are equal

70 =3x+1

Subtract 1 from each side

69 = 3x

Divide by 3

69/3 =3x/3

23 =x

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Vanyuwa [196]
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3 years ago
Solve the equation x/4 - 7 = y for x
expeople1 [14]

Answer:

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Step-by-step explanation:

x/4 - 7 = y

+7              +7

x/4 = y + 7

× 4             × 4

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7 0
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Read 2 more answers
(1+tanx)/(sinx+cosx)=secx
jek_recluse [69]

\frac{1+\tan x}{\sin x+\cos x}=\sec x is proved

<h3><u>Solution:</u></h3>

Given that,

\frac{1+\tan x}{\sin x+\cos x}=\sec x  ------- (1)

First we will simplify the LHS and then compare it with RHS

\text { L. H.S }=\frac{1+\tan x}{\sin x+\cos x}  ------ (2)

\text {We know that } \tan x=\frac{\sin x}{\cos x}

Substitute this in eqn (2)

=\frac{1+\frac{\sin x}{\cos x}}{\sin x+\cos x}

On simplification we get,

=\frac{\frac{\sin x+\cos x}{\cos x}}{\sin x+\cos x}

=\frac{\sin x+\cos x}{\cos x} \times \frac{1}{\sin x+\cos x}

Cancelling the common terms (sinx + cosx)

=\frac{1}{c o s x}

We know secant is inverse of cosine

=\sec x=R . H . S

Thus L.H.S = R.H.S

\frac{1+\tan x}{\sin x+\cos x}=\sec x

Hence proved

5 0
3 years ago
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