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ExtremeBDS [4]
2 years ago
6

Help!!!

Mathematics
1 answer:
Serhud [2]2 years ago
8 0

Answer:

your answer would be 2 and 1/5 :) hope this helps

Step-by-step explanation:

-Rayne

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7^3 times 7^-7 times 7
dusya [7]

Hello there! :)

<u><em>Answer:\frac{1}{343}</em></u>

<u><em>*The answer must have a fraction.*</em></u>

Step-by-step explanation:

Lesson: Zero and Negative Exponents.

Distributive property: a(b+c)=ab+ac

First, you apply exponent rule.

a^b*a^c=a^b^+^c

7^-^3

\frac{1}{7^3}=7^3=7*7*7=343

Final answer: \frac{1}{343}

Hope this helps!

Thanks!

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Have a great day!

:)

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Show that if x and y may both be written as the sum of the squares of two rational integers, then their product xy may also be w
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Answer:

See proof below

Step-by-step explanation:

One way to solve this problem is to "add a zero" to complete the required squares in the expression of xy.

Let x=m^2+n^2 and y=l^2+k^2 with m,n,l,k\in \mathbb{Z}. Multiplying the two equations with the distributive law and reordering the result with the commutative law, we get xy=(m^2+n^2)(l^2+k^2)=m^2l^2+m^2k^2+n^2l^2+n^2k^2=n^2l^2+m^2k^2+m^2l^2+n^2k^2

Now, note that 0=2lkmn-2lkmn=2nkml-2nlmk by the commutativity of rational integers. Add this convenient zero the the previous equation to obtain xy=n^2l^2-2nlmk+m^2k^2+m^2l^2+2nkml+n^2k^2=(nl-mk)^2+(ml+nk)^2, thus xy is the sum of the squares of nl-mk,ml+nk\in \mathbb{Z}.

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3 years ago
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Step-by-step explanation:

put the value of y and get the value of x.then plot it in graph.(try to get non fractional values)

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