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2 years ago

Help!!!

Mathematics

1 answer:

Serhud [2]2 years ago

8 0

Answer:

your answer would be 2 and 1/5 :) hope this helps

Step-by-step explanation:

-Rayne

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32 divided by a number c

Drupady [299]

32/C would be the answer-

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2 years ago

Help please timed :(((

Alik [6]

A because you move down 5 units and over 2

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2 years ago

7^3 times 7^-7 times 7

dusya [7]

Hello there! :)

Answer: $\frac{1}{343}$

*The answer must have a fraction.*

Step-by-step explanation:

Lesson: Zero and Negative Exponents.

Distributive property: a(b+c)=ab+ac

First, you apply exponent rule.

$a^b*a^c=a^b^+^c$

$7^-^3$

$\frac{1}{7^3}=7^3=7*7*7=343$

Final answer: $\frac{1}{343}$

Hope this helps!

Thanks!

-Charlie

Have a great day!

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3 years ago

Show that if x and y may both be written as the sum of the squares of two rational integers, then their product xy may also be w

Georgia [21]

Answer:

See proof below

Step-by-step explanation:

One way to solve this problem is to "add a zero" to complete the required squares in the expression of xy.

Let $x=m^2+n^2$ and $y=l^2+k^2$ with $m,n,l,k\in \mathbb{Z}$ . Multiplying the two equations with the distributive law and reordering the result with the commutative law, we get $xy=(m^2+n^2)(l^2+k^2)=m^2l^2+m^2k^2+n^2l^2+n^2k^2=n^2l^2+m^2k^2+m^2l^2+n^2k^2$

Now, note that $0=2lkmn-2lkmn=2nkml-2nlmk$ by the commutativity of rational integers. Add this convenient zero the the previous equation to obtain $xy=n^2l^2-2nlmk+m^2k^2+m^2l^2+2nkml+n^2k^2=(nl-mk)^2+(ml+nk)^2$ , thus xy is the sum of the squares of $nl-mk,ml+nk\in \mathbb{Z}$ .

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3 years ago

Math graphs Find the graph

Nadya [2.5K]

Step-by-step explanation:

put the value of y and get the value of x.then plot it in graph.(try to get non fractional values)

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2 years ago