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3 years ago

Pls plsplsplssplslslpslpslplpslslpslps

Mathematics

2 answers:

daser333 [38]3 years ago

8 0

Answer:

Step-by-step explanation:

10 x 5= 50/2 = 25

igor_vitrenko [27]3 years ago

3 0

25 because 10x5 is 50 divided by 2 is 25

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the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 56 in, find its length and width

lisabon 2012 [21]

Answer:

Step-by-step explanation:

Let the width of the rectangle = x

As length is 5 inches longer than width, we have to add 5 to width

Length = x + 5

Perimeter of ractangle = 56 in

2* (length + width) = 56

2*( x + 5 + x) = 56

2* (2x + 5) = 56

Use distributive property: a*(b +c) =(a*b) + (a * c)

2*2x + 2*5 = 56

4x + 10 = 56

Subtract 10 from both sides

4x = 56- 10

4x = 46

Divide both sides by 4

x = 46/4

x = 11.5

Width = 11.5 in

length = 11.5 + 5

= 16.5 in

3 0

2 years ago

Prove that 25^9+5^17is divisible by 30

VLD [36.1K]

Answer:

proof is below

Step-by-step explanation:

Answer:

25^9 + 5^17=

=2^18 + 5^17

=5^17(5+1)

=5^17×6

=5^16×30 is divisible by 30

6 0

2 years ago

Greatest to least 1.202, 1.29, 1.02

Lady bird [3.3K]

If you were to list these numbers in order from greatest to least, it would be 1.29, 1.202, 1.02.
Hope this helps!!

7 0

3 years ago

Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

3 years ago

solve the system of equations below by graphing both equations with a pencil and paper. what is the solution y = x - 1 y = 1/2x

Elan Coil [88]

Answer:

(4,3)

Step-by-step explanation:

$(x-1) = \frac{1}{2}x +1$

$(x-\frac{1}{2}x)-(-1+1)=(\frac{1}{2}x-\frac{1}{2}x)+(1+1)$

$(\frac{1}{2}x/\frac{1}{2})=(2/\frac{1}{2})$

$x=4$

$y=(4)-1$

$y=3$

$y=\frac{1}{2}(4)+1$

$y=2+1$

$y=3$

6 0

3 years ago