Answer:
(i) (f - g)(x) = x² + 2·x + 1
(ii) (f + g)(x) = x² + 4·x + 3
(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2
Step-by-step explanation:
The given functions are;
f(x) = x² + 3·x + 2
g(x) = x + 1
(i) (f - g)(x) = f(x) - g(x)
∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1
(f - g)(x) = x² + 2·x + 1
(ii) (f + g)(x) = f(x) + g(x)
∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3
(f + g)(x) = x² + 4·x + 3
(iii) (f·g)(x) = f(x) × g(x)
∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2
(f·g)(x) = x³ + 4·x² + 5·x + 2
Photo please? and a function means that it cant have the same number of x axis'
example,
function;
15 6
-46 37
36 -37
27 -25
not a function;
-1 3
5 7
-5 6
-1 8
Answer:
this should be the graph.
Step-by-step explanation:
I hope this helps.
Answer:
Step-by-step explanation:
Think of drawing a right triangle, with the hypotenuse connected to points A and B. The hypotenuse, or the distance between A and B is 2√10. 2√10 is the same thing as √40. Thus, because of Pythagorean theorem, a^2 + b^2 = 40. One combination would be a=2 and b = 6 and another would be a = 6 and b = 2. Thus, the two places point B could be are (3,7) and (7,3).
Hope it helps <3