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Fed [463]
3 years ago
9

In the figure above, the vertices of quadrilateral A B C D lie on the sides of quadrilateral P Q R S. What is the sum of the deg

ree measures of the eight indicated angles?

Mathematics
1 answer:
Aleks04 [339]3 years ago
7 0
The vertices of the quadrilateral ABCD lie on the sides of quadrilateral PQRS then the sum of the degree of measures of the eight indicated angles would be 360.
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Help please i give thanks lol
maks197457 [2]
What is question . .
7 0
3 years ago
Apply the distributive property to factor out the greatest common factor. 18d+12 =18d+12=18, d, plus, 12, equals
kobusy [5.1K]

Answer:

\huge\boxed{6 ( 3d + 2 )}

Step-by-step explanation:

18d + 12

The greatest common factor is 6, So we need to factor out 6

=> 6 ( 3d + 2 ) [Distributive property has been applied and this is the simplest form]

6 0
2 years ago
Read 2 more answers
a band that will be the opening act for a concert charges a $700.00 flat fee as well as 16% of all ticket profits from ticket sa
Fofino [41]
The band earned $1,200.

1. Subtract the flat fee 1,200-700 =500
2. 500 is what just the band made. Divide that by .16 (16%) to get the total ticket amount... 500 divided by .16 = 3,125

The total ticket amount was $3,125.
5 0
2 years ago
The daily mean temperature in a particular place is 83. how many cooling-degree days were accumulated?
olga55 [171]
Degree days are the difference between the daily temperature mean, (high temperature plus low temperature divided by two) and 65°F. 65°F because we assume that at this temperature we do not need cooling or heating. 
In our case the daily mean temperature is 83°F and X is the number of cooling-degree days.
X=83-65
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4 0
3 years ago
Which pair of numbers have a GCF of 2? Choose all answers that are correct. A. 10 and 2 B. 4 and 6 C. 6 and 12 D. 2 and 24
il63 [147K]
A.
<span>GCF(10; 2) = 2  /</span>factors of 10: 1, 2, 5, 10; factors of 2: 1, 2/

B.
GCF(4; 6) = 2  /factors of 4: 1, 2, 4; factors of 6: 1, <span>2, 3, 6/</span>

C.
GCF(6; 12) = 6  /factors of 6: 1, 2, 3, 6; factors of 12: 1, <span>2, 3, 4, 6, 12/</span>

D.
GCF(2; 24) = 2   <span>/factors of 2: 1, 2; factors of 24: 1, <span>2, 3, 4, 6, 8, 12, 24/</span>

</span>Answer: A, B and D.


8 0
3 years ago
Read 2 more answers
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