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3 years ago

14

On a fishing trip, you catch two fish. The weight of the first fish is 1.2 LB. The second fish weighs at least 0.5 pound more th

an the first fish. Write an inequality that represents the possible weights w (in pounds) of the second fish.

1 answer:

Masteriza [31]3 years ago

8 0

that would be

w ≥ 1.2 + 0.5

w ≥ 1.7 answer

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What is the slope? helpppp?

EleoNora [17]

Answer:

slope: -(9/8)

y-intercept: 7

equation: y = -(9/8)x + 7

Step-by-step explanation:

Solve for the slope.

<em>m</em> (slope) = (y₂ - y₁)/(x₂ - x₁)

Let:

(x₁ , y₁) = (8 , -2)

(x₂ , y₂) = (0 , 7)

Plug in the corresponding numbers to the corresponding variables:

<em>m </em>= (7 - (-2))/(0 - 8)

<em>m</em> = (7 + 2)/(0 - 8)

<em>m</em> = 9/-8

Your slope is -(9/8)

Solve for the y-intercept. Plug in your slope into the slope intercept form:

y = mx + b

Let:

(x , y) = (0 , 7) & m = -(9/8)

Plug in the corresponding numbers to the corresponding variables:

7 = -(9/8)(0) + b

Simplify:

7 = (-9/8 * 0) + b

7 = (0) + b

b = 7

Your y-intercept is 7.

~

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3 years ago

Write an equation in slope intercept form of the line passing through (5,-4) and is perpendicular to a line whose equation is -2

Sergeu [11.5K]

Rearrange the given equation in slope intercept form
$y = \frac{3x - 1}{ - 2} \\ y = - \frac{3}{2} x + \frac{1}{2}$
slope of the required line is
$- \frac{1}{ - \frac{3}{2} } = \frac{2}{3}$
equation is given by
$y - y1 = m(x - x1) \\ y - - 4 = \frac{2}{3} (x - 5) \\ y + 4 = \frac{2x}{3} - \frac{10}{3} \\ y = \frac{2x}{3} - \frac{10}{3} - 4 \\ y = \frac{2}{3} x - \frac{22}{3}$

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3 years ago

Joe's new car travel 418 miles on 16 gallons of gas find the unit rate in miles per gallon show your work I will Mark brainiest

seraphim [82]

To find the unit rate, divide total miles by number of gallons:

418 miles / 16 gallons = 26.125 miles per gallon
Round the answer as needed.

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3 years ago

Please help me with this!

Airida [17]

Step-by-step explanation:

→ 42 = 7u - u

→ 42 = 6u

→ 42/6 = u

→ 7 =u or U = 7

<em><u>hope </u></em><em><u>this</u></em><em><u> answer</u></em><em><u> helps</u></em><em><u> you</u></em><em><u> dear</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care </u></em><em><u>and</u></em><em><u> may</u></em><em><u> u</u></em><em><u> have</u></em><em><u> a</u></em><em><u> great</u></em><em><u> day</u></em><em><u> ahead</u></em><em><u>!</u></em>

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3 years ago

Algebra problem, please show work!

Brrunno [24]

6x+1 / 2x +6 - 5/2

Factor 2 out of the denominator of the first fraction:

6x+1 / 2(x+3) - 5/2

Rewrite 5/2 to have a common denominator with the first fraction:

6x+1/2(x+3) - 5(x+3) / 2(x+3)

Simplify terms:

6x +1 - 5(x+3) / 2(x+3)

Use distributive property:

6x +1 - 5x -15 / 2(x+3)

Combine like terms for final answer:

(x-14) / 2(x+3)

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3 years ago