9 more than the product of 51 and the number t

Mathematics

2 answers:

ElenaW [278]2 years ago

7 0

It is 60 because 51+9 is 60

Leya [2.2K]2 years ago

6 0

It is 60 hope i helped a lot

You might be interested in

last year, marys vegetable garden was a rectangle that measured 6 ft by 8 ft. If she wants to increase the size this year by a s

il63 [147K]

The new one will measure 12 ft by 16 ft

8 0

2 years ago

{A number line from negative 10 to 10 with tick marks every 1 unit. A closed dot is at negative 3 with a ray pointing left from

maks197457 [2]

Draw a number line from -10 to +10 with tick marks (division lines) every 1 unit. Now find the origin (in the middle of the line you have just drawn). Now move your pencil point 3 units to the left and plot a dark (closed) dot there. Then draw a ray from that closed dot to the left. Apparently we cannot extend that ray beyond -10.

(-10,-3] would be my representation of this situation.

6 0

3 years ago

Solve the equation for x∈Z -x² +8x -14 ≥ 0

kenny6666 [7]

$ax^2+bx+c=0\\\Delta=b^2-4ac\\if\ \Delta < 0\ then\ no\ solutions\\if\ \Delta=0\ then\ one\ solution:x=\frac{-b}{2a}\\if\ \Delta > 0\ then\ two\ solutions:x=\frac{-b\pm\sqrt\Delta}{2a}\\================================\\\\-x^2+8x-14\geq0\ \ \ \ |multiply\ both\ sides\ by\ (-1)\ \{change\ \geq\ on\ \leq\}\\\\x^2-8x+14\leq0\\\\a=1;\ b=-8;\ c=14\\\\\Delta=(-8)^2-4\cdot1\cdot14=64-56=8 > 0\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=\sqrt4\cdot\sqrt2=2\sqrt2$

$x_1=\frac{-(-8)-2\sqrt2}{2\cdot1}=\frac{8-2\sqrt2}{2}=\frac{8}{2}-\frac{2\sqrt2}{2}=\boxed{4-\sqrt2}\\\\x_2=\frac{-(-8)+2\sqrt2}{2\cdot1}=\frac{8+2\sqrt2}{2}=\frac{8}{2}+\frac{2\sqrt2}{2}=\boxed{4+\sqrt2}\\\\============================$

$ax^2+bx+c=0\\\\if\ a > 0\ then\ the\ parabola\ o pen\ up\\if\ a < 0\ then\ the\ parabola\ o pen\ down\\========================\\\\a=1 > 0-therefore\ o pen\ up\ (look\ at\ the\ picture)\\\\===============================\\\\Answer:x\in\left$

$Solutions\ in\ \mathbb{Z}:\\\\\sqrt2\approx1.4\\\\threfore:4-\sqrt2\approx4-1.4=2.6\ and\ 4+\sqrt2\approx4+1.4=5.4\\\\look\ at\ the\ second\ picture:x=3\ or\ x=4\ or\ x=5\ (x\in\{3;\ 4;\ 5\})$