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solong [7]
3 years ago
9

(dH/dt)=k(68-H) find the general solution for the differential equation

Mathematics
1 answer:
Anni [7]3 years ago
4 0
DH/dt=k(68-H)
1/(68-H)dH=kt assuming k is a constant
ln|68-H|=kt+C (*)
we have all H satisfying (*)
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The solutions to the given equation containing absolute value term |3x-7| - 7 = x are 0 and 7.

<h3>What are the solutions to the given equation?</h3>

Given the equation in question;

|3x-7| - 7 = x

First, add 7 to both sides.

|3x-7| - 7 + 7 = x + 7

|3x-7|  = x + 7

Next, remove the absolute value term, this creates a ± on the right side of the question.

|3x-7|  = x + 7

3x-7  = ±( x + 7 )

The complete solution is the result of both the negative and positive portions of the solution.

For the first solution, use the positive of ±.

3x-7  = ( x + 7 )

3x - 7  =  x + 7  

3x - x = 7 + 7

2x = 14

x - 14/2

x = 7

For the second solution, use the negative of ±.

3x-7  = -( x + 7 )

3x-7  = -x - 7

3x + x = -7 + 7

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x = 0/4

x = 0

Therefore, the solutions to the given equation containing absolute value term |3x-7| - 7 = x are 0 and 7.

Learn to solve more equation involving absolute value term here: brainly.com/question/28635030

#SPJ1

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