C^2+(2/3)
2^2+(2/3)
4+(2/3)
4 2/3
Final answer: 4 2/3 or 14/3 as an improper fraction
Answer:
2520 patterns
Step-by-step explanation:
In 'n' 10! ways, books can be arranged. But, there are also 5! permutation of blue books 'n1', 2! permutation of identical green books 'n2', and 3! permutation identical black books 'n3'.
Therefore, for non identical arrangements:
![\frac{n!}{n1!n2!n3!}](https://tex.z-dn.net/?f=%5Cfrac%7Bn%21%7D%7Bn1%21n2%21n3%21%7D)
= 2520
Therefore, the books can be arranged on a shelf in 2520 patterns
Answer:
x<3/8
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Step-by-step explanation:
Step 1: Simplify both sides of the inequality.
x+1/4<5/8
Step 2: Subtract 1/4 from both sides.
x + 1/4 - 1/4 < 5/8 - 1/4
x<3/8
Answer:
![12 x^{7}](https://tex.z-dn.net/?f=12%20x%5E%7B7%7D)
Step-by-step explanation:
We can say that exchanging one couple's ticket for an individual's ticket would increase the money in the cash box from 200 to 202 and it would result in an even number of couples tickets sold.
<u>Step-by-step explanation:</u>
Let the number of tickets sold to the individuals = s
Let the number of tickets sold to the couples = c
According to the question,
s + c = 46 ( Equation 1)
Since each individual's ticket is $6, the total amount of money made by selling tickets to individuals is 6s.
Similarly, since each ticket sold to couples is $8, the total amount of money made by selling tickets to couples is 8c.
So,
6 s + 8 c = 200 ( Equation 2)
On solving both the equations, we get
c = 38 and s = 8
Therefore, 8 tickets were sold to individuals and 38 tickets were sold to the couples.