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Brrunno [24]
3 years ago
10

How would one solve this

Mathematics
1 answer:
yaroslaw [1]3 years ago
4 0
Sorry i really need points
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0.0009999 as a fraction
Kobotan [32]

9999/10000000

Because if you read it, it would be read as "nine thousand 10 millionths."

3 0
4 years ago
<img src="https://tex.z-dn.net/?f=0%20%3D%20%20%5Cfrac%7Bi%7D%7B8%7D%20" id="TexFormula1" title="0 = \frac{i}{8} " alt="0 = \f
alekssr [168]

Answer:

0

Step-by-step explanation:

i/8=0

i=0*8

i=0

3 0
4 years ago
Read 2 more answers
I need help finding the area and the equation to it.
RideAnS [48]

Hello from MrBillDoesMath!


Answer:

3 1/2   (i.e 3.5)


Discussion:

From the attached file, the area of the shaded triangle =

Area  =   <u>square</u> surrounding triangle -

               area triangle 1 - area triangle  2 -  area triangle 3


         = 4 * 4  -

             (1/2) (1 * 1)     -  (1/2) (3 * 4)  -   (1/2) (3 * 4)

         = 16  - 1/2 - 1/2 (12) - 1/2(12) =

         = 16 - 1/2 - 12 =

         = 4 - 1/2

         = 3 1/2


Where we have used that the area of a triangle =

(1/2) base * height.


Thank you,

MrB

6 0
4 years ago
Evaluate arccos (-1/2)
Crazy boy [7]

Answer:

120 degrees

Step-by-step explanation:

plugged into calculator

cos inverse of -1/2

Please mark Brainliest if you feel like it:)

3 0
3 years ago
In the following figure CB is perpendicular to AB, and CD bisects angle ACB. Find angle DBF
zaharov [31]
Measure angle ACD = 3x - 2
measure angle BCD = 5x - 20
measure angle ACD = measure angle BCD
3x - 2 = 5x - 20
-2 = 2x - 20
18 = 2x
9 = x
x = 9
measure angle BCD = 5x - 20
measure angle BCD = 5(9) - 20
measure angle BCD = 45 - 20
measure angle BCD = 25
measure angle CDA = 90
measure angle BDC = measure angle CDA
measure angle BDC = 90
measure angle DBF = measure angle BCD + measure angle BDC
measure angle DBF = 25 + 90
measure angle DBF = 115
5 0
3 years ago
Read 2 more answers
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