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3 years ago

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15PTS!!!! HELPPPP!!! Determine the length of fencing around an 80 m by 170 m rectangular playing field if fence is to be 25 m ou

tside the edge of playing field

1 answer:

marshall27 [118]3 years ago

5 0

Perimeter=2L+2W, in this case L=80+2(25) and W=170+2(25) so

P=2(L+W)=2(80+50+170+50)

P=2(350)=700m

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Yoshi is painting a large wall in the park. He measures the wall and finds that the dimensions are 4 m by 20 m. Yoshi has a can

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No. The area of a square/rectangle is length * height, and 4 * 20 is 80m^2. Because Yoshi has a can of paint that can cover 81m^2, and 81m^2 > 80m^2, Yoshi does NOT need to buy more paint.

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3 years ago

A random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6. A random sample of 17 su

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Answer:

We conclude that there is no difference in potential mean sales per market in Region 1 and 2.

Step-by-step explanation:

We are given that a random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6.

A random sample of 17 supermarkets from Region 2 had a mean sales of 78.3 with a standard deviation of 8.5.

Let $\mu_1$ = mean sales per market in Region 1.

$\mu_2$ = mean sales per market in Region 2.

So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2$ = 0 {means that there is no difference in potential mean sales per market in Region 1 and 2}

Alternate Hypothesis, $H_A$ : > $\mu_1-\mu_2\neq$ 0 {means that there is a difference in potential mean sales per market in Region 1 and 2}

The test statistics that will be used here is <u>Two-sample t-test statistics</u> because we don't know about population standard deviations;

T.S. = $\frac{(\bar X_1 -\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+ {\frac{1}{n_2}}} }$ ~ $t__n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean sales in Region 1 = 84

$\bar X_2$ = sample mean sales in Region 2 = 78.3

$s_1$ = sample standard deviation of sales in Region 1 = 6.6

$s_2$ = sample standard deviation of sales in Region 2 = 8.5

$n_1$ = sample of supermarkets from Region 1 = 12

$n_2$ = sample of supermarkets from Region 2 = 17

Also, $s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $s_p=\sqrt{\frac{(12-1)\times 6.6^{2}+(17-1)\times 8.5^{2} }{12+17-2} }$ = 7.782

So, <u><em>the test statistics</em></u> = $\frac{(84-78.3)-(0)}{7.782 \times \sqrt{\frac{1}{12}+ {\frac{1}{17}}} }$ ~ $t_2_7$

= 1.943

The value of t-test statistics is 1.943.

Now, at a 0.02 level of significance, the t table gives a critical value of -2.472 and 2.473 at 27 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have<u><em> insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that there is no difference in potential mean sales per market in Region 1 and 2.

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3 years ago

A scientist from the United States conducts an experiment using miles per hour to measure speed why might this be confusing for

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The scientific mathematical language barrier.

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3 years ago

Jamya is making a rectangular blanket. The length of the blanket is 10inches greater than it's worth, W, in inches. Write the fu

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Answer: (w² + 10)inches²

Step-by-step explanation:

Since the width of the rectangular blanket is given as w and the length of the blanket is 10inches greater than it's width, therefore the length will be:

= 10 + w.

Therefore,

length = 10 + w

width = w

Area = length × width

Area = (10 + w) × w

Area = 10w + w²

Therefore, the area of the blanket will be (w² + 10)inches².

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3 years ago

Moon Company produces baseball bats and cricket paddles. It has two departments that process all products – Cutting Department a

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The Moon Company's equivalents units for <em>transferred-in cost, direct materials, and conversion cost</em> are 74,800 / 101,200 / 86,800 respectively.

Data and Calculations:

Percentage of completion:

Beginning work in process = 80%

Ending work in process = 30%

Beginning inventories:

Transferred-in costs = $30,800

Direct materials costs = $13,200

Conversion costs = $27,500

Physical Flows of Units:

Beginning WIP = 26,400

Units transferred in from Cutting Department = 74,800

Total production units available = 101,200 (26,400 + 74,800)

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Transferred-in Direct Materials Conversion

Units transferred out 79,200 79,200

(79,200 x 100%)

Units transferred-in 74,800 0 0

(74,800 x 100%)

Ending WIP 0 22,000 (100%) 6,600 (22,000 x 30%)

Total equivalent units 74,800 101,200 86,800

Thus, the equivalent units for the Finishing Department are determined based on the percentage of completion under the Weighted Average Method.

Learn more: brainly.com/question/17078653

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3 years ago