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german
3 years ago
12

CU,

Mathematics
1 answer:
yarga [219]3 years ago
4 0

Answer:

b

Step-by-step explanation:

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Raju’s father’s age is 5 years more than three times Raju’s age. Find Raju’s age,
Harrizon [31]

Answer:

Step-by-step explanation:

In order to find the answer, let's work backwards to find the original. We have to do the opposite to get to the Raju's age. We will start with his fathers age. (44) Then we will subtract five from it so that it will be divisible by three.

44 - 5 = 39

Then we just have to divide by 3.

44/3 = 13

His age is 13 years old.

5 0
3 years ago
Which of the following verifies that AABC is similar to A DEF?
Archy [21]
Similarity cannot he determined but I’m not sure
8 0
3 years ago
Nathan deposited 7/9 of his allowance into his savings account. He spent the remaining amount, or $2.50. How much did Nathan dep
kati45 [8]
Let us assume that total amount of Nathan's allowance = x
Amount of money deposited by Nathan into his savings account = 7x/9
Remaining amount that Nathan spent = $2.50
Now we have to get to the equation for solving the question asked.
7x/9 + 2.50 = x
7x + (9 * 2.50) = 9x
7x + 22.50 = 9x
22.50 = 9x - 7x
22.50 =2x
x = 22.50/2
   = 11.25
So $11.25 is the total allowance of Nathan.
Then The amount of money deposited by
Nathan in savings account = (7/9) * 11.25
                                           = 78.75/9
                                           = 8.75
So Nathan deposits $8.75 in his savings account.
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5 0
3 years ago
Jeremy caught 8 fish in a contest.
seraphim [82]

Answer:

3.1 kg

Step-by-step explanation:

4.3+5.3+ 6.8+ 2.6 + 3.2 +4.4 +4.8= 31.4 kg

Last fish= y

(31.4 + y)÷ 8= 4.3125

31.4 + y= 4.3125 x 8

y= 34.5 - 31.4

∴ y= 3.1 kg

6 0
3 years ago
Help me please!!! i cant do these
LuckyWell [14K]

Answer:

sec(B)=b. ab/bc

sin(B)=c. ac/ab

csc(B)=f. ab/ac

cot(B)=a. bc/ac

tan(B)=e. ac/bc

cos(B)=d. bc/ab

Step-by-step explanation:

<u><em>SOHCAHTOA</em></u>

<u><em>Sine=Opposite/Hypotenuse</em></u>

<u><em>Cosine=Adjacent/Hypotenuse</em></u>

<u><em>Tangent=Opposite/Adjacent</em></u>

<u><em>SHACHOCotAO</em></u>

<u><em>Secant=Hypotenuse/Adjacent</em></u>

<u><em>Cosecant=Hypotenuse/Opposite</em></u>

<u><em>Cotangent=Adjacent/Opposite</em></u>

<u><em /></u>

6 0
1 year ago
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