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kow [346]
3 years ago
15

The displacement of a particle on a vibrating string is given by the equation s(t)=11+1/4sin(14PIt), where s is measured in cent

imeters and in seconds. Find the velocity of the particle after t seconds.
Mathematics
1 answer:
Lelechka [254]3 years ago
6 0
<span>Find the first derivative of the given expression.

</span>s(t)=11+\frac{ 1 }{ 4}\sin(14{\pi}t) &#10;\\&#10;\\s^{'}(t)=v(t)=\frac{ 7 }{ 2 }{\pi}\cos(14{\pi}t)<span>
</span>
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Please explain with working!!! Find the set of values of x that satisfy the inequality 9x^2-15x&lt;6
Oksi-84 [34.3K]

Answer:

-1/3

Step-by-step explanation:

When solving a quadratic inequality, first solve it normally like you would for a normal quadratic equation. We have:

9x^2-15x

Ignore the less than sign and replace it with an equal sign and solve the quadratic for its zeros:

9x^2-15x=6

Subtract 6 from both sides:

9x^2-15x-6=0

Divide everything by 3:

3x^2-5x-2=0

Factor. Find two numbers that equal (3)(-2)=-6 that add up to -5.

-6 and 1 works. Thus:

3x^2-6x+x-2=0\\3x(x-2)+1(x-2)=0\\(3x+1)(x-2)=0

Find the x using the Zero Product Property:

3x+1=0 \text{ or }x-2=0\\x=-1/3\text{ or }x=2

Now, we need to replace the equal signs with symbols again. To do so, we need to test which symbol to place. Let's do the first zero first.

So, the first zero is:

x=-1/3

Assume that the correct symbol is >. Thus,

x>-1/3

Now, pick any number that is greater than -1/3. I'll pick 0 since it's the easiest. Now, plug 0 back into the very original inequality. If it works, then the sign is correct, if it doesn't, then simply use the opposite one. Therefore:

9x^2-15x

0 is indeed less than six, so our first correct solution is:

x>-1/3

For the second one, do the same thing. We have:

x=2

Assume that the correct symbol is <. Thus:

x

Again, pick any number less than 2. I'm going to use 0. Plug 0 back into the original equation

9x^2-15x

Again, this is correct. Therefore, x<2 is also the correct inequality.

So together, we have:

x>-1/3 \text{ and } x

Together, we can write them as:

-1/3

(Note that we don't need to worry about the "or equal to" part since the original inequality didn't have it.)

6 0
3 years ago
What is the data point that is the farthest from other data points when the box plot is NOT symmetrical?
Naddika [18.5K]

Answer: B. Outlier

Step-by-step explanation:

An outlier is an extremely large or extremely small data value in a data set such that it appears far from the other data points when we plot data points on scatter plot or box plot.

Thus, the data point that is the farthest from other data points when the box plot is NOT symmetrical is Outlier.

Its presence affects the value of mean directly. So when a data set have outliers , we prefer Median(Mid value of a data set) as the best measure of central tendency because existence of outliers does not effect Median .

Hence, the correct option is B. Outlier.

5 0
3 years ago
The value 5pi/24 is a solution for the equation 4 cos^2 (4x)-3=0. True or false
Margaret [11]

Let's check.

x = 5π/24

4x = 5π/6

cos 4x = cos(5π/6) = cos 150° = -√3/2

cos² 4x = (-√3/2)^2 = 3/4

4 cos² 4x  -3  = 4 (3/4) - 3 = 0

Answer: TRUE

5 0
3 years ago
2 ratios equivalent to 8\3
borishaifa [10]

Some equivalent fractions of 8/3 are:
8/3 = 16/6 = 24/9 = 32/12 = 40/15 = 48/18 = 56/21 = 64/24 = 72/27 = 80/30 = 88/33 = 96/36 = 104/39 = 112/42 = 120/45 = 128/48 = 136/51 = 144/54 = 152/57 = 160/60
3 0
3 years ago
Evaluate the expression when m=4 and n=48
andrew-mc [135]
What’s the expression
3 0
3 years ago
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