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Nookie1986 [14]

3 years ago

7

340 over 8 as a unit rate

2 answers:

Alexxandr [17]3 years ago

6 0

340 170 85 1
------ = ------- = ------ = 42 ---
8 4 2 2

hope helped

Anastasy [175]3 years ago

4 0

340/8 = 42.50 per unit

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Can I get some help on this please

slamgirl [31]

2=12
i know that one for a fact u just have to mutiply

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3 years ago

An urn contains 6 red balls, 8 green balls, and 10 white balls. If balls are selected one by one (without replacing them after t

PIT_PIT [208]

Answer:

0.43478

Step-by-step explanation:

From the information given:

$The \ required \ probability = P(1st ball = red) \times P(2nd ball = red) + P(1st ball = red) \times P(2nd ball = white) + P(2nd ball = red) \times P(1st ball = white) + P(1st ball = white) \times P(2nd ball = white)$

$= \dfrac{6}{6+8+10}\times \dfrac{5}{5+8+10} + \dfrac{6}{6+8+10} \times \dfrac{10}{5+8+10} + \dfrac{10}{6+8+10} \times \dfrac{6}{5+8+10} \times \dfrac{10}{6+8+10} \times \dfrac{9}{5+8+9}$

$=(\dfrac{6}{24}\times \dfrac{5}{23})+ (\dfrac{6}{24}\times \dfrac{10}{23}) +( \dfrac{10}{24}\times \dfrac{6}{23} ) + (\dfrac{10}{24}\times \dfrac{9}{23})$

= 0.05434782609 + 0.1086956522 + 0.1086956522 + 0.1630434783

= 0.4347826088

≅ 0.43478

8 0

2 years ago

48% of the students in the class play sports. 12 students in the class play sports , how many students are in the class?

Setler [38]

The answer is 25 students.

3 0

3 years ago

Read 2 more answers

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

Paha777 [63]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

We know that,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

Using the trigonometric ratios, we get

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Hence, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

6 0

3 years ago

How do you call the number pair that is used to describe a point on a plane

Degger [83]

Answer:

Maybe ordered pair

Step-by-step explanation:

I'm guessing you meant like what is it called

5 0

3 years ago