Answer:
1. Going to the close store is cheaper.
Step-by-step explanation:
The difference in the prices of chicken is 3.19 -2.89 = 0.30 per pound, so for 5 pounds of chicken, the far store offers a price that totals 5×$0.30 = $1.50 less.
The difference in travel distances is 8.4 -2.4 = 6 miles, so the total round-trip distance difference is 12 miles. The cost of gas is ...
($3.81 /gal)/(23 mi/gal) = $0.1656 /mi
so the cost of gas for the 12-mile longer trip would be
12×$0.1656 ≈ $1.99
Traveling to the far store, you would spend $1.99 more on gas to save $1.50 on the price of chicken. Going to the close store is cheaper.
Hi there!
Let's start by replacing "a number" by the letter "x" so that we can do an equation and isolate "x" to find your answer :
(x - 
) + 
= -7
subtract on each side of the equation
x - = -8.25
add on each side of the equation
x = -7.5
-7.5 - 3/4 = -8.25
-8.25 + 5/4 = <u>-7</u>
So your answer is : Three-fourths was subtracted from -7.5, and then 5/4 was added to the result. The sum was -7.
There you go! I really hope this helped, if there's anything just let me know! :)
The volume of the prism is calculated by multiplying the length, L, width,W, and depth or height, H.
V = L x W x H
Fish tank:
V = 50 cm x 25 cm x 25 cm
= 31250 cm³
Depth of the water in tank (with castle - without castle)
d = 57.5 cm - 48 cm = 9.5 cm
Volume of the caste:
V = 9.5 cm x 50 cm x 25 cm = 11875 cm³
13/20,3/5,29/50,14/25,53/100
5)
a. The equation that describes the forces which act in the x-direction:
<span> Fx = 200 * cos 30 </span>
<span>
b. The equation which describes the forces which act in the y-direction: </span>
<span> Fy = 200 * sin 30 </span>
<span>c. The x and y components of the force of tension: </span>
<span> Tx = Fx = 200 * cos 30 </span>
<span> Ty = Fy = 200 * sin 30 </span>
d.<span>Since desk does not budge, </span><span>frictional force = Fx
= 200 * cos 30 </span>
<span> Normal force </span><span>= 50 * g - Fy
= 50 g - 200 * sin 30
</span>____________________________________________________________
6)<span> Let F_net = 0</span>
a. The equation that describes the forces which act in the x-direction:
(200N)cos(30) - F_s = 0
b. The equation that describes the forces which act in the y-direction:
F_N - (200N)sin(30) - mg = 0
c. The values of friction and normal forces will be:
Friction force= (200N)cos(30),
The Normal force is not 490N in either case...
Case 1 (pulling up)
F_N = mg - (200N)sin(30) = 50g - 100N = 390N
Case 2 (pushing down)
F_N = mg + (200N)sin(30) = 50g + 100N = 590N
