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mezya [45]
3 years ago
12

Find all the zeros of the function f(x)=x^3+15x^2+67x+53

Mathematics
1 answer:
Elza [17]3 years ago
7 0
<span> x = 3<span> x =(-12-√-4)/-2=6+i= 6.0000-1.0000i</span><span> x =(-12+√-4)/-2=6-i= 6.0000+1.000</span></span>
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Find the measure of A <br><br> A:46<br> B:90<br> C:134<br> D:88
grigory [225]

Answer:

Option d = 88

Step-by-step explanation:

Angle c = 46 degrees

46 + 46 = 92

180 - 92 = 88

5 0
3 years ago
Read 2 more answers
10ft 19 ft how do you do this
tino4ka555 [31]
 If we're talking about a box with dimensions 10 ft, 19 ft and 20 ft, it's probable that the instructions say to calculate the volume.  That would be

V = (10 ft)(19 ft)(20 ft) = 3800 cubic feet.
8 0
3 years ago
the cost of an annual tuition at a university increased from 10,500 to 11,300 what is the percent increase in tuition to the nea
Maurinko [17]
Percent increase
find increase first
10500 to 11300
11300-10500=800
so
percent increase
change/original
origianal=10500
change=800
800/10500=8/105=0.0761
percent means parts out of 100
0.0761/1 times 100/100=7.61/100=7.61%

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7.6%

5 0
3 years ago
Solve for x: 2(x 3)2 − 4 = 0 Round your answer to the nearest hundredth. X = 4. 41, 1. 59 x = 1. 34, 5. 24 x = −1. 34, −5. 24 x
gladu [14]

The two values when the provided quadratic equation is solved for the x are -4.41 and -1.59 to the nearest hundredth.

<h3>What is a quadratic equation?</h3>

A quadratic equation is the equation in which the unknown variable is one and the highest power of the unknown variable is two.

The standard form of the quadratic equation is,

ax^2+bx+c=0

Here, (<em>a,b,c</em>) are the real numbers and <em>x </em>is the variable.

To find the value of x, the following formula is used,

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

The given equation is,

2(x+ 3)^2 - 4 = 0

To solve this equation, we need to apply some mathematical operations over it. Let's start with opening the brackets.

2(x+ 3)^2 - 4 = 0\\2(x^2+6x+9)-4=0\\2x^2+12x+14-4\\2x^2+12x+12=0\\x^2+6x+7=0

On comparing with standard equation we get,

a=1, b=6, c=7

Put this values in the above formula,

x=\dfrac{-(6)\pm\sqrt{(6)^2-4(1)(7)}}{2(1)}\\x=\dfrac{-(6)\pm\sqrt{(6)^2-4(1)(7)}}{2(1)}\\x=-4.41,-1.59

Hence, the two values when the provided quadratic equation is solved for the x are -4.41 and -1.59 to the nearest hundredth.

Learn more about the quadratic equation here;

brainly.com/question/1214333

5 0
2 years ago
If y=1/2*x+3, which ordered pair is one of the solutions for the equation and the coordinates for one of the points on
AleksAgata [21]

Step-by-step explanation:

D (-2,2)

:) good day

good day

6 0
3 years ago
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