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mezya [45]
3 years ago
12

Find all the zeros of the function f(x)=x^3+15x^2+67x+53

Mathematics
1 answer:
Elza [17]3 years ago
7 0
<span> x = 3<span> x =(-12-√-4)/-2=6+i= 6.0000-1.0000i</span><span> x =(-12+√-4)/-2=6-i= 6.0000+1.000</span></span>
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What is the solution to -55+q=7<br><br> A. a=-62<br><br> B. q=62<br><br> C. q=42<br><br> D. q=-42
Scorpion4ik [409]

Answer:

C, as q = 62.

Step-by-step explanation:

When you have an equation, your goal is to get the letter you are solving for alone. To do this, you employ a simple rule: what you do to one side of the equals sign, you must do the other.

To isolate q in -55 + q = 7, you must add 55 to the left side. q is now alone. However, because we added 55 to the left side, we must also do it to the right! 7 + 55 = 62, so the new right side is 62. Hence, we get to this:

q = 62

The answer is now in plain sight!

4 0
2 years ago
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8(x-a) = 2(2a - x). Solve for. X
Mariulka [41]

Hey! Your answer would be x = 6a/5

8 0
2 years ago
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6(6v +6) - 5 = 1 + 6v<br><br> Need answer with explaination
Tresset [83]

Answer:

v=-1

Step-by-Step Explanation:

6 0
2 years ago
Read 2 more answers
Please help___________​
kramer

Answer:

Step-by-step explanation:

Let's do the obvious things first.

Right rectangle

w = 11

L = 17

Formula

Area = L * W

Area = 11 * 17

Area =                                                187

Left rectangle

W = 8

L = 11

Area = 8 * 11=                                      88

Middle Rectangle

W = 11

L = 15

Area = 11 * 15                                    165

Now we come to the triangles. It's not obvious what to do with them. You have to infer that one of the lets is 8 and the other is 15. You get the 8 from the width of the left rectangle (see above.)

There are 2 triangles

Area = 2 * 1/2 * l1 * l2

Leg 1 = 8

Leg2 = 15

Area = 2 * 1/2 (8 * 15)

Area =               <u>                            120 </u>

Total  = 120 + 165 + 88 + 187 =    560

Unless you have an  E answer that is 560, my answer does not agree with any of the given answers. I would suggest that you ask your teacher how it is done. My method is correct.

4 0
2 years ago
Show that the equation x^4/2021 − 2021x^2 − x − 3 = 0 has at least two real roots.
andreev551 [17]

The roots of an equation are simply the x-intercepts of the equation.

See below for the proof that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} has at least two real roots

The equation is given as: \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}

There are several ways to show that an equation has real roots, one of these ways is by using graphs.

See attachment for the graph of \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}

Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)

From the attached graph, we can see that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500

This means that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} has at least two real roots

Read more about roots of an equation at:

brainly.com/question/12912962

6 0
3 years ago
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