3 years ago

Find all the zeros of the function f(x)=x^3+15x^2+67x+53

1 answer:

Elza [17]3 years ago

7 0

x = 3 x =(-12-√-4)/-2=6+i= 6.0000-1.0000i x =(-12+√-4)/-2=6-i= 6.0000+1.000

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IrinaVladis [17]

The rule is +4
how did you find it you can 87-91=4
so that is your rule +4

8 0

3 years ago

KATRIN_1 [288]

Answer:

(x + 1, y - 3)

Step-by-step explanation:

The translation is 1 unit right and 3 units down.

7 0

3 years ago

Kazeer [188]

Answer:

$x^{2} - 5x - 24$

Step-by-step explanation:

( x + 3 )( x - 8 ) =

$x^{2}$ - 8x + 3x - 24 = $x^{2}$ - 5x -24

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3 years ago

adelina 88 [10]

C bc i am a professor at Yale and it is simplistic...............................................................

6 0

3 years ago

Mariulka [41]

Use o fato de que o determinante de qualquer matriz quadrada é o mesmo da sua transposta.

$\mathbf A=\begin{bmatrix}1&-2&1\\-3&1&4\\0&6&8\end{bmatrix}$

$\mathbf B=\mathbf A^\top=\begin{bmatrix}1&-3&0\\-2&1&6\\1&4&8\end{bmatrix}$

3 0

3 years ago