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Gwar [14]
2 years ago
5

If i have $40.00 to spend and 1 pound of food costs $0.40 cents. How many pounds of food would i be able to buy?

Mathematics
2 answers:
lbvjy [14]2 years ago
7 0
$100 answer is very easy ok
Ivanshal [37]2 years ago
4 0

Answer:

40/.40 = 100

You can buy 100 pounds of food.

Step-by-step explanation:

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3 years ago
What is the slope intercept form of (3, -2) and (0,4)
Levart [38]

Answer:

Slope is 2/-1 the equation would be y=2/-1x+4

Step-by-step explanation:

Use the formula of y2-y1/x2-x1 to find the slope

Plot the two points on a graph and find the y int. (:

Hope this helped!

4 0
3 years ago
What’s the answer??
Natasha2012 [34]

Answer: For the top one, Y=24 and for the bottom one Y=48

Step-by-step explanation:

For the top you just multiply 3 by 8 and for the bottom one you isolate the variable by dividing each side by factors that don't contain the variable.

7 0
3 years ago
Pls help and show workings
oksano4ka [1.4K]

Answer: x = 15

Step-by-step explanation:

same thing. here's my work:

<em>4x - 5 = 3x + 10</em>

<em>4x - 5 (+ 5) = 3x + 10 (+ 5)</em>

<em>4x = 3x + 15</em>

<em>4x (- 3x) = 3x (- 3x) + 15</em>

x = 15

5 0
2 years ago
Consider the following data set which relates the hemoglobin levels h (kg/dL) of workers and the altitude a (km) above the sea l
Nikolay [14]

Answer:

The highest permanently tolerable altitude is 52.53 km.

Step-by-step explanation:

We have to calculate the maximum altitude that the residents/workers can tolerate.

This altitude is at which the hemoglobin conventration is 0.001 of the concentration at sea level.

We can express that as:

\frac{h_{max}}{h_0}=\frac{c_1e^{-c_2a_{max}}}{c_1e^0} =e^{-c_2a_{max}}=0.001\\\\-c_2*a_{max}=ln(0.001)\\\\a_{max}=-ln(0.001)/c_2=6.9078/0.1315\\\\a_{max}=52.5308

The highest permanently tolerable altitude is 52.53 km.

6 0
3 years ago
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